Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 4)
4.
In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Answer: Option
Explanation:
Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.
New C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs. 420.
Profit = Rs. (420 - 125) = Rs. 295.
![]() |
![]() |
295 | x 100 | ![]() |
= | 1475 | % = 70% (approximately). |
420 | 21 |
Video Explanation: https://youtu.be/bQA8SB8ycbw
Discussion:
146 comments Page 2 of 15.
Rahul Singh said:
10 years ago
Let C.P = 100.
When C.P = 100 then profit will be profit = (320/100)*100 = 320.
When C.P = 100 and Profit = 320 then S.P = (C.P+Profit) = (320+100) = 420.
If the C.P increases by 25% Then C.P = 125 and S.P according numerical remain constant.
So S.P = 420.
Now profit will be profit = (S.P-C.P) = 420-125 = 295.
So Required % = (295/420)*100 = approx (70).
When C.P = 100 then profit will be profit = (320/100)*100 = 320.
When C.P = 100 and Profit = 320 then S.P = (C.P+Profit) = (320+100) = 420.
If the C.P increases by 25% Then C.P = 125 and S.P according numerical remain constant.
So S.P = 420.
Now profit will be profit = (S.P-C.P) = 420-125 = 295.
So Required % = (295/420)*100 = approx (70).
Nza said:
1 decade ago
Yes what you did is good. Please this also challenges me. You can help me.
Assume that the district tax revenues grow at 25%. The district authority believes that its financial needs will be satisfied when the tax revenues double. As the local revenue collection officer, you are approached to tell when that will happen, holding other factors constant.
Assume that the district tax revenues grow at 25%. The district authority believes that its financial needs will be satisfied when the tax revenues double. As the local revenue collection officer, you are approached to tell when that will happen, holding other factors constant.
Nids said:
1 decade ago
Lets assume cost to be 10.
profit = 320/100*10
=32.
S.P = CP + P
=10+32
=42.
Now cost increased by 25% (25/100*10=2.5)
=10 + 2.5
=12.5.
SP remaining the same 42
SP=C + p
42 =12.5 + x
29.5 = x.
So,
If 42 is 100, how much would be 29.5?
Cross multiply
42=100.
29.5=?
Ans: 70.
profit = 320/100*10
=32.
S.P = CP + P
=10+32
=42.
Now cost increased by 25% (25/100*10=2.5)
=10 + 2.5
=12.5.
SP remaining the same 42
SP=C + p
42 =12.5 + x
29.5 = x.
So,
If 42 is 100, how much would be 29.5?
Cross multiply
42=100.
29.5=?
Ans: 70.
Subhojit Mukherjee said:
5 years ago
Give Profit = 320% of CP = 3.2CP.
SP-CP = 3.2CP.
SP = 4.2CP.
New CP = CP+(25% of CP).
New CP = CP+(CP/4).
New CP = 1.25CP.
New Profit = SP- New CP.
New Profit = 4.2CP - 1.25CP.
New Profit = 2.95CP.
Required Percentage = (2.95CP/4.2CP)*100.
= 70.23%.
= 70%(approximately),
SP-CP = 3.2CP.
SP = 4.2CP.
New CP = CP+(25% of CP).
New CP = CP+(CP/4).
New CP = 1.25CP.
New Profit = SP- New CP.
New Profit = 4.2CP - 1.25CP.
New Profit = 2.95CP.
Required Percentage = (2.95CP/4.2CP)*100.
= 70.23%.
= 70%(approximately),
(6)
Omare Oréna said:
3 years ago
(Gain/C.P)*100 = 320.
Taking C.P as 'x' & S.P as 'y',
We can get S.P as a function of C.P:
(y-x)/x = 320/100.
y=4.2x.
Gain as a percentage of S.P when only C.P increases by 25%:
New C.P = x + 25x/100.
= 1.25x.
S.P = y = 4.2x i.e unchanged.
(S.P - C.P)*100/S.P = (4.2x - 1.25x)*100/4.2x.
= 70%.
Taking C.P as 'x' & S.P as 'y',
We can get S.P as a function of C.P:
(y-x)/x = 320/100.
y=4.2x.
Gain as a percentage of S.P when only C.P increases by 25%:
New C.P = x + 25x/100.
= 1.25x.
S.P = y = 4.2x i.e unchanged.
(S.P - C.P)*100/S.P = (4.2x - 1.25x)*100/4.2x.
= 70%.
(6)
Hariom Dubey said:
9 years ago
In general, we calculate profit % relative to C. P (because CP remains constant) but if we are asked to calculate profit % relative to S. P (as in this question) we have to take S. P.
As base price provided S. P is given constant. Since in this question S. P is given constant, we can take S. P as the base price.
As base price provided S. P is given constant. Since in this question S. P is given constant, we can take S. P as the base price.
Kushal Obroy said:
1 year ago
Let C.P = x,
Given,
Profit Percentage: 320% of C.P.
Then
S.P = Gain - C.P
= 320x/100 - x = 220x/100.
Now, C.P increased by 25% then,
New C.P. = 125x /100.
Then,
New Gain = S.P. - C.P.
= 220x/100 - 125x/100,
= 95x/100.
Then, New Profit Percentage = (Gain * 100)/100.
= (95x/100)*100 /(125x/100).
= 76%.
Given,
Profit Percentage: 320% of C.P.
Then
S.P = Gain - C.P
= 320x/100 - x = 220x/100.
Now, C.P increased by 25% then,
New C.P. = 125x /100.
Then,
New Gain = S.P. - C.P.
= 220x/100 - 125x/100,
= 95x/100.
Then, New Profit Percentage = (Gain * 100)/100.
= (95x/100)*100 /(125x/100).
= 76%.
(9)
Blurryface said:
2 years ago
Given :
P = 3.2*C.P
= S.P - C.P --->
Thus, S.P = 4.2*C.P
C.P'(new C.P) = 1.25*C.P.
Asked : {P'(new profit)/S.P} * 100.
Solution : P' = S.P - C.P'
= S.P - 1.25*C.P' ---> Given
= S.P - 1.25*(S.P/4.2) ---> Given
=(59/84)*S.P.
Therefore
(P'/S.P)*100 = (59/84)*100 = 70.24 %.
P = 3.2*C.P
= S.P - C.P --->
Thus, S.P = 4.2*C.P
C.P'(new C.P) = 1.25*C.P.
Asked : {P'(new profit)/S.P} * 100.
Solution : P' = S.P - C.P'
= S.P - 1.25*C.P' ---> Given
= S.P - 1.25*(S.P/4.2) ---> Given
=(59/84)*S.P.
Therefore
(P'/S.P)*100 = (59/84)*100 = 70.24 %.
(12)
Kshitiz Vaya said:
3 years ago
Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 420.
Profit = Rs. (420 - 125) = Rs. 295.
Required percentage = (Profit/Cost Price) * 100 = Rs. (295/125)*100 = 236%
Ans = 250% (approximately).
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 420.
Profit = Rs. (420 - 125) = Rs. 295.
Required percentage = (Profit/Cost Price) * 100 = Rs. (295/125)*100 = 236%
Ans = 250% (approximately).
(73)
Vaibhav Pund said:
8 years ago
It's so simple.
Assume CP=100.
Then SP=320% of CP=(100*320)/100=320+100=420.
CP increased by 25%=100*25%=(100*25)/100=25+100=125,
Profit=SP-CP=420-125=295.
Profit %=( gain/CP)*100.
But we have to find profit% with SP.
So,
Profit %=(295/420)*100=70%.
Assume CP=100.
Then SP=320% of CP=(100*320)/100=320+100=420.
CP increased by 25%=100*25%=(100*25)/100=25+100=125,
Profit=SP-CP=420-125=295.
Profit %=( gain/CP)*100.
But we have to find profit% with SP.
So,
Profit %=(295/420)*100=70%.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers