Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 4)
4.
In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Answer: Option
Explanation:
Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.
New C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs. 420.
Profit = Rs. (420 - 125) = Rs. 295.
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295 | x 100 | ![]() |
= | 1475 | % = 70% (approximately). |
420 | 21 |
Video Explanation: https://youtu.be/bQA8SB8ycbw
Discussion:
147 comments Page 12 of 15.
Sandy said:
1 decade ago
Why don't we do like this:
We know that p = S.P-C.P.
If x% be selling percentage of profit then,
x*S.P = S.P-C.P.
S.P- (x*S.P) = C.P.
S.P (1-x) = C.P.
(S.P/C.P) = (1/1-x).
Now when we see the problem he given a clue that p = 320% (C.P).
S.P-C.P = (320/100) (C.P).
S.P-C.P = (3.2) C.P.
S.P = (3.2) C.P+C.P.
S.P = (4.2) C.P.
S.P/C.P = 4.2 =>A.
When C.P increases 25%, S.P is remains same then.
S.P/ (C.P+ (25%C.P) ) = (1/1-x).
S.P/ (1+0.25) C.P = (1/1-x).
S.P/ (1.25) C.P = (1/1-x).
(1/1.25) (S.P/C.P) = (1/1-x).
Substituting from A (S.P/C.P) = 4.2.
(1\1.25) (4.2) = (1/1-x).
(3.36) = (1/1-x).
(1-x) = (1/3.36).
1-x = (25/84).
x = 1- (25/84).
x = (59/84) = ~70% (approximately).
We know that p = S.P-C.P.
If x% be selling percentage of profit then,
x*S.P = S.P-C.P.
S.P- (x*S.P) = C.P.
S.P (1-x) = C.P.
(S.P/C.P) = (1/1-x).
Now when we see the problem he given a clue that p = 320% (C.P).
S.P-C.P = (320/100) (C.P).
S.P-C.P = (3.2) C.P.
S.P = (3.2) C.P+C.P.
S.P = (4.2) C.P.
S.P/C.P = 4.2 =>A.
When C.P increases 25%, S.P is remains same then.
S.P/ (C.P+ (25%C.P) ) = (1/1-x).
S.P/ (1+0.25) C.P = (1/1-x).
S.P/ (1.25) C.P = (1/1-x).
(1/1.25) (S.P/C.P) = (1/1-x).
Substituting from A (S.P/C.P) = 4.2.
(1\1.25) (4.2) = (1/1-x).
(3.36) = (1/1-x).
(1-x) = (1/3.36).
1-x = (25/84).
x = 1- (25/84).
x = (59/84) = ~70% (approximately).
Nids said:
1 decade ago
Lets assume cost to be 10.
profit = 320/100*10
=32.
S.P = CP + P
=10+32
=42.
Now cost increased by 25% (25/100*10=2.5)
=10 + 2.5
=12.5.
SP remaining the same 42
SP=C + p
42 =12.5 + x
29.5 = x.
So,
If 42 is 100, how much would be 29.5?
Cross multiply
42=100.
29.5=?
Ans: 70.
profit = 320/100*10
=32.
S.P = CP + P
=10+32
=42.
Now cost increased by 25% (25/100*10=2.5)
=10 + 2.5
=12.5.
SP remaining the same 42
SP=C + p
42 =12.5 + x
29.5 = x.
So,
If 42 is 100, how much would be 29.5?
Cross multiply
42=100.
29.5=?
Ans: 70.
Sujith shetty said:
1 decade ago
Just assume cost of price is 100 then profit is 320 so total cost of product is 320+100=420 if cost increases 25% i.e 125 then profit decreases 420-125=295(profit) 295/420*100=70%
Lekan said:
1 decade ago
Alright I have another method here without assumption. First things first.
P=SP-CP. Since P=(320/100)CP Then (320/100)CP=SP-CP. SP=(420/100)CP
Next thing is getting the second equation. Our target is "what percentage of the selling price SP is the profit,P if we have a new cost price of (125/100)CP while SP remains the same?" So keep another P in mind which is x per cent of SP.
Therefore equation2 is xSP/100=SP-(125/100)CP
So xSP=100SP-125CP.
SP=(420/100)CP
xSP=100SP-125CP Eq2.
Substituting for SP in Eq2 then we have
x(420/100)CP=100(420/100)CP-125CP
xCP420/100=420CP-125CP. xCP420/100=295CP. x=295/4.2 x=70.23.
Note it has to be an approximated value according to the question which is 70.
P=SP-CP. Since P=(320/100)CP Then (320/100)CP=SP-CP. SP=(420/100)CP
Next thing is getting the second equation. Our target is "what percentage of the selling price SP is the profit,P if we have a new cost price of (125/100)CP while SP remains the same?" So keep another P in mind which is x per cent of SP.
Therefore equation2 is xSP/100=SP-(125/100)CP
So xSP=100SP-125CP.
SP=(420/100)CP
xSP=100SP-125CP Eq2.
Substituting for SP in Eq2 then we have
x(420/100)CP=100(420/100)CP-125CP
xCP420/100=420CP-125CP. xCP420/100=295CP. x=295/4.2 x=70.23.
Note it has to be an approximated value according to the question which is 70.
Ann said:
1 decade ago
Good explanation Malini!
Dinu said:
1 decade ago
@Mohana.
They have given profit%=320%. So to calculate profit we use the formula profit%= (profit*100) /C.P.
If you assume C.P=100 then always the profit% = profit for this simplicity we always assume C.P=100.
They have given profit%=320%. So to calculate profit we use the formula profit%= (profit*100) /C.P.
If you assume C.P=100 then always the profit% = profit for this simplicity we always assume C.P=100.
Mohana said:
1 decade ago
How they have taken the C.P value = 100
even it gives change to assume any number like 1,2,3, etc.,
even it gives change to assume any number like 1,2,3, etc.,
Sagar khurd said:
1 decade ago
25% cp is 1250 how that value get.
Merlin said:
1 decade ago
Why we are taking cp as 100?
In what cases we should assume in that way.
2. Why cannt we take that as x as in above sums.
In what cases we should assume in that way.
2. Why cannt we take that as x as in above sums.
Mittalvarun2011 said:
1 decade ago
Thanks Nitesh and malini for such a nice explanation.
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