Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
306 comments Page 6 of 31.
DaniA said:
1 decade ago
3(y - x) = (2y - x) In this eqn how you subtract x from 2y?
I can not undestand pls explain.
I can not undestand pls explain.
Aakash kathunia said:
1 decade ago
I am also not able to understand how you substract x from 2y.. please explain... plz
PRASAD said:
1 decade ago
Balaji explained well thank you very much.
Kiran said:
1 decade ago
Still I m unable to understand this problem please help me out.
M.V.KRISHNA said:
1 decade ago
3(y - x)=(2y - x)
This step is not clear for me.
Alternate method:
S.P = C.P + PROFIT.............(1)
2*S.P = C.P + 3*PROFIT...........(2)
eq(2) - eq(1)
S.P = 2* PROFIT
SUBST S.P IN (1), WE GET
2* PROFIT = C.P + PROFIT
therefore, PROFIT = C.P
PROFIT % = (PROFIT / C.P) * 100
FINALLY, PROFIT % = 100%
This step is not clear for me.
Alternate method:
S.P = C.P + PROFIT.............(1)
2*S.P = C.P + 3*PROFIT...........(2)
eq(2) - eq(1)
S.P = 2* PROFIT
SUBST S.P IN (1), WE GET
2* PROFIT = C.P + PROFIT
therefore, PROFIT = C.P
PROFIT % = (PROFIT / C.P) * 100
FINALLY, PROFIT % = 100%
Karthic.v said:
1 decade ago
Help. Please give me an another way to solve the problem.
SURAJ SAHOO said:
1 decade ago
LET C.P= 10
S.P= 20
SO, PROFIT= (20-10)I.E (SP-CP)
ACC TO THE QUES,
IF S.P DOUBLES I.E 2(20) THEN
PROFIT TRIPLES I.E 3(20-10).
SO, PROFIT PERCNT= (PROFIT/CP)*100
= {3(20-10)/10}*100
= 300%.
S.P= 20
SO, PROFIT= (20-10)I.E (SP-CP)
ACC TO THE QUES,
IF S.P DOUBLES I.E 2(20) THEN
PROFIT TRIPLES I.E 3(20-10).
SO, PROFIT PERCNT= (PROFIT/CP)*100
= {3(20-10)/10}*100
= 300%.
Ashish said:
1 decade ago
Profit = s.p - c.p ---(1)
3(profit)=2s.p - c.p ---(2)
-----------------------
solving equ 1 nd 2... we get
s.p = 2(profit) ---- (3)
substitute equ (3) in equ (1)... we get
c.p = profit ---- (4)
using (3) nd (4) if c.p=1 then s.p=2 and profit=1
hence, profit% = (profit/c.p)*100 = 100%
3(profit)=2s.p - c.p ---(2)
-----------------------
solving equ 1 nd 2... we get
s.p = 2(profit) ---- (3)
substitute equ (3) in equ (1)... we get
c.p = profit ---- (4)
using (3) nd (4) if c.p=1 then s.p=2 and profit=1
hence, profit% = (profit/c.p)*100 = 100%
Atul said:
1 decade ago
Cost price x , selling price y, profit (y-x).
If selling price is doubled =2y , then new profit will be (2y-x)
which 3 times the original profit i.e. (y-x)
there fore new profit (2y-x)= 3x old profit (x-y)
That is (2y-x)=3(x-y).
If selling price is doubled =2y , then new profit will be (2y-x)
which 3 times the original profit i.e. (y-x)
there fore new profit (2y-x)= 3x old profit (x-y)
That is (2y-x)=3(x-y).
Srinivas said:
1 decade ago
@Balaji well done.
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