Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
303 comments Page 4 of 31.
Savitha said:
1 decade ago
Guneet thanks I got it clearly !
Pratyusha said:
1 decade ago
How can you write profit=3(y-x)=2y-x ? Please can any one tell me.
Swetha said:
1 decade ago
@Pratyusha
Refer balaji's explaination..very clear. No body can explain more than him.
Well done balaji!
Refer balaji's explaination..very clear. No body can explain more than him.
Well done balaji!
Narayanan said:
1 decade ago
Ya..balaji's explanation is clear Profit= y-x___________(1)
From the data given, if selling price doubles, profit will be tribled. So that
From(1), we can write
Profit = y-x, here from the data given if y doubles profit will be tribled. so we can write in place of profit we can write y-x
3(y-x) = 2y-x.
From the data given, if selling price doubles, profit will be tribled. So that
From(1), we can write
Profit = y-x, here from the data given if y doubles profit will be tribled. so we can write in place of profit we can write y-x
3(y-x) = 2y-x.
Tushar Vaibhav said:
1 decade ago
PROFIT = 3(Y-X)= (2Y-X)
= 3Y-3X-2Y+X
= 1Y-2X
(i.e)Y=2X : Profit = (Y-X)(i.e) =(2x-x)=Rs.x
Profit% = C.P/profitX100= X/X*100=100%.
FROM HERE EXPLAIN CLEARLY.
= 3Y-3X-2Y+X
= 1Y-2X
(i.e)Y=2X : Profit = (Y-X)(i.e) =(2x-x)=Rs.x
Profit% = C.P/profitX100= X/X*100=100%.
FROM HERE EXPLAIN CLEARLY.
Sindhu said:
1 decade ago
See balaji explaination. Its very clear.
Hamzah Bhatti said:
1 decade ago
Let Cost Price Be X AND Selling Price be Y And Profit for this is Z, THEN BY given Condition
((y-x)/x)*100=Z -------------- (1)
Similarly By Given Condition
((2y-x)/x)*100 =3Z Or Z = ((2Y-X)/3X)*100 -------- (2)
Both eqn 1 and 2 are equal equating these two eqn gives
3(y-x) =2y-x
y=2x
Put this value in eqn 1 and get z = 100.
((y-x)/x)*100=Z -------------- (1)
Similarly By Given Condition
((2y-x)/x)*100 =3Z Or Z = ((2Y-X)/3X)*100 -------- (2)
Both eqn 1 and 2 are equal equating these two eqn gives
3(y-x) =2y-x
y=2x
Put this value in eqn 1 and get z = 100.
Ramkumar said:
1 decade ago
Thanks Satish. Its really simple.
Shree said:
1 decade ago
Raj answer is so simple:).
Ravi said:
1 decade ago
Thanks @balaji
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