Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
306 comments Page 4 of 31.
Pavani said:
4 years ago
I think the answer is wrong.
2Sp = 2profit.
2sp = 2 (sp-cp),
3cp = 2sp,
Profit = 1.
Profit% = 50.
2Sp = 2profit.
2sp = 2 (sp-cp),
3cp = 2sp,
Profit = 1.
Profit% = 50.
Neeraj said:
4 years ago
I have a doubt, is the question asking to calculate profit before doubling the SP or after?
Let us assume SP = Rs 6, CP = Rs 3, Profit = Rs 3.
As per question new SP = Rs 12, CP will remain same Rs 3 , Profit = Rs 9 ( triple of previous).
in 1st case P% = P/CPx100 = 3/3 x100 = 100%.
in 2nd case P% = 9/3 x100 = 300%.
Please confirm what is specified by the question? Profit in 1st case or 2nd case. Please explain me.
Let us assume SP = Rs 6, CP = Rs 3, Profit = Rs 3.
As per question new SP = Rs 12, CP will remain same Rs 3 , Profit = Rs 9 ( triple of previous).
in 1st case P% = P/CPx100 = 3/3 x100 = 100%.
in 2nd case P% = 9/3 x100 = 300%.
Please confirm what is specified by the question? Profit in 1st case or 2nd case. Please explain me.
(4)
Neeraj said:
4 years ago
I have a doubt, is the question asking to calculate profit before doubling the SP or after?
Let us assume SP = Rs 6, CP = Rs 3, Profit = Rs 3.
As per question new SP = Rs 12, CP will remain same Rs 3 , Profit = Rs 9 ( triple of previous).
in 1st case P% = P/CPx100 = 3/3 x100 = 100%.
in 2nd case P% = 9/3 x100 = 300%.
Please confirm what is specified by the question? Profit in 1st case or 2nd case. Please explain me.
Let us assume SP = Rs 6, CP = Rs 3, Profit = Rs 3.
As per question new SP = Rs 12, CP will remain same Rs 3 , Profit = Rs 9 ( triple of previous).
in 1st case P% = P/CPx100 = 3/3 x100 = 100%.
in 2nd case P% = 9/3 x100 = 300%.
Please confirm what is specified by the question? Profit in 1st case or 2nd case. Please explain me.
(1)
Soham Garai said:
4 years ago
Let me clear it;
LET THE CP BE Rs; x.
AND LET THE SP BE Rs y.
So, PROFIT = y - x.
But, HERE AS MENTIONED PROFIT TRIPLES AND SP DOUBLES;
SO,3(y-x) = 2y-x.
3y-3x = 2y-x.
y = 2x(SP).
PROFIT = 2x-x = x.
PROFIT % = x/x * 100=100(HERE X is profit and X is CP).
LET THE CP BE Rs; x.
AND LET THE SP BE Rs y.
So, PROFIT = y - x.
But, HERE AS MENTIONED PROFIT TRIPLES AND SP DOUBLES;
SO,3(y-x) = 2y-x.
3y-3x = 2y-x.
y = 2x(SP).
PROFIT = 2x-x = x.
PROFIT % = x/x * 100=100(HERE X is profit and X is CP).
Saran said:
4 years ago
Let the C.P be Rs.100 and S.P be Rs.x, Then;
The profit is (x-100),
Now the S.P is doubled, then the new S.P is 2x,
New profit is (2x-100),
Now as per the given condition;
=> 3(x-100) = 2x-100.
By solving, we get;
x = 200.
Then the Profit percent = (200-100) * 100/100 = 100,
Hence the profit percentage is 100%.
The profit is (x-100),
Now the S.P is doubled, then the new S.P is 2x,
New profit is (2x-100),
Now as per the given condition;
=> 3(x-100) = 2x-100.
By solving, we get;
x = 200.
Then the Profit percent = (200-100) * 100/100 = 100,
Hence the profit percentage is 100%.
Madhavi said:
4 years ago
It's clearly mentioned in the question.
i) 2S.P - C.P = 3Profit
ii)Profit = S.P - C.P.
Now substitute ii in i, then you will get,
2S.P-C.P = 3(S.P-C.P).
After the simplification.
S.P = 2C.P.
* iii) (S.P/C.P)=2.
Now we have to find the profit%.
Profit%=((S.P-C.P)/C.P)*100 = {(S.P/C.P)-1}*100.
Substituting iii in above will give you (2-1)*100 = 100,
So the Profit %=100.
i) 2S.P - C.P = 3Profit
ii)Profit = S.P - C.P.
Now substitute ii in i, then you will get,
2S.P-C.P = 3(S.P-C.P).
After the simplification.
S.P = 2C.P.
* iii) (S.P/C.P)=2.
Now we have to find the profit%.
Profit%=((S.P-C.P)/C.P)*100 = {(S.P/C.P)-1}*100.
Substituting iii in above will give you (2-1)*100 = 100,
So the Profit %=100.
(1)
Rohan said:
4 years ago
@Poonam.
The statement is if s.p is doubled then profit triples and using the formula of profit in this statement, c.p.= X s.p.=Y formula of;
profit=s.p. - c.p. so, 3 ( profit = s.p - c.p )
3 (Y-X)=(2Y-X).
The statement is if s.p is doubled then profit triples and using the formula of profit in this statement, c.p.= X s.p.=Y formula of;
profit=s.p. - c.p. so, 3 ( profit = s.p - c.p )
3 (Y-X)=(2Y-X).
Rohan said:
4 years ago
Hi;
In this equation, the statement is if s.p. is doubling then profit triples I.e c.p is x and s.p is y. Therefore ३ (y-x)=(२y-x) then in this equation why x is involved in २y-x the only sp is doubled then profit triples, so why x cp is involved?
In this equation, the statement is if s.p. is doubling then profit triples I.e c.p is x and s.p is y. Therefore ३ (y-x)=(२y-x) then in this equation why x is involved in २y-x the only sp is doubled then profit triples, so why x cp is involved?
Elvina said:
4 years ago
profit1 = sp-cp.
profit2 = 2sp-cp.
profit2 = 3times profit1,
2sp-cp = 3(sp-cp),
sp = 2cp.
Therefore profit % = (sp-cp)100/cp = (2cp-cp)100/cp,
cp will get cancelled,
profit% = 100.
profit2 = 2sp-cp.
profit2 = 3times profit1,
2sp-cp = 3(sp-cp),
sp = 2cp.
Therefore profit % = (sp-cp)100/cp = (2cp-cp)100/cp,
cp will get cancelled,
profit% = 100.
Anu said:
4 years ago
@Ashwini.
We could assume C. P as 100.
Now by the given condition,
If C. P = 100 than S. P = 2*100 = 200.
So now using profit % formula;
(S. P - C.P)*100/C.P,
S. P - C. P = 200 - 100 = 100 ; and also C.P = 100,
So, profit% = 100 *100/100,
Hence, the profit% = 100.
We could assume C. P as 100.
Now by the given condition,
If C. P = 100 than S. P = 2*100 = 200.
So now using profit % formula;
(S. P - C.P)*100/C.P,
S. P - C. P = 200 - 100 = 100 ; and also C.P = 100,
So, profit% = 100 *100/100,
Hence, the profit% = 100.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers