Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
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x | x 100 | ![]() |
x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
303 comments Page 28 of 31.
Vijay Prasanth A said:
6 years ago
Here for profit % we need to take profit as 2y-x or 3(y-x) but you take it as y-x.
I think we assume profit has tripled.
I think we assume profit has tripled.
Vagisha said:
6 years ago
FROM %P FORMULA.
WE KNOW;
SP = ((100+%P) /100 ) *CP
so 100 and CP being constant we have the relation
SP is directly proportional to 100+%P
thus;
SP1/SP2 = (100+%P1) / (100+%P2).
Given SP=2SP.
And P = 3P.
THUS
SP / 2SP = (100+P)/(100+3P).
On simplifying;
100+3P = 200+2P,
GIVING
P = 100.
WE KNOW;
SP = ((100+%P) /100 ) *CP
so 100 and CP being constant we have the relation
SP is directly proportional to 100+%P
thus;
SP1/SP2 = (100+%P1) / (100+%P2).
Given SP=2SP.
And P = 3P.
THUS
SP / 2SP = (100+P)/(100+3P).
On simplifying;
100+3P = 200+2P,
GIVING
P = 100.
Devamanen said:
6 years ago
Guys,
It's simple.
For example
Sp =rs100,
Sp =rs110.
Now, Sp is doubled.
(ie) :sp=2(110) rs=>220 but remember cp remains the same.
Then, we know.
1) profit=sp-cp
2) profit %= (sp-cp/cp)100.
From the question;
If Sp is doubled the profit triple so with this we build the equation.
2sp-cp = 3(profit).
(ie)
2sp-cp=3(sp-cp).
We get
Sp=2cp ---> (1)
To find profit %
(Sp-cp/cp) 100.
Sub 1 in the formula above;
(2cp-cp/cp)100.
So, finally, we get 100%.
It's simple.
For example
Sp =rs100,
Sp =rs110.
Now, Sp is doubled.
(ie) :sp=2(110) rs=>220 but remember cp remains the same.
Then, we know.
1) profit=sp-cp
2) profit %= (sp-cp/cp)100.
From the question;
If Sp is doubled the profit triple so with this we build the equation.
2sp-cp = 3(profit).
(ie)
2sp-cp=3(sp-cp).
We get
Sp=2cp ---> (1)
To find profit %
(Sp-cp/cp) 100.
Sub 1 in the formula above;
(2cp-cp/cp)100.
So, finally, we get 100%.
Anomii said:
6 years ago
Why did you take 3(y-x) = (2y-x)?
Can someone please explain?
Can someone please explain?
Sahil Mayekar said:
6 years ago
P : Profit.
X : Price.
R : RATE.
INITIALLY,
X + P = X + XR/100.
P = XR/100 -----------(1).
BUT WHEN WE DOUBLES THE PRICE,
X + 3P = 2X + 2XR.
BECAUSE WE WANT TO FIND R,
3P = X + 2XR/100.
P = (X + (2XR/100))/3.
Put above P in Equation (1).
(X + (2XR/100))/3 = XR/100.
X + 2XR/100 = 3XR/100.
X = XR/100.
100 = R.
R = 100%.
X : Price.
R : RATE.
INITIALLY,
X + P = X + XR/100.
P = XR/100 -----------(1).
BUT WHEN WE DOUBLES THE PRICE,
X + 3P = 2X + 2XR.
BECAUSE WE WANT TO FIND R,
3P = X + 2XR/100.
P = (X + (2XR/100))/3.
Put above P in Equation (1).
(X + (2XR/100))/3 = XR/100.
X + 2XR/100 = 3XR/100.
X = XR/100.
100 = R.
R = 100%.
Siddu 324 said:
6 years ago
Assume CP = x then SP increase double of CP.
Then SP = 2x.
Formula for gain% = {(gain) X 100/CP}.
Then gain%= (x/x) X 100.
Then finally gain% = 100.
Then SP = 2x.
Formula for gain% = {(gain) X 100/CP}.
Then gain%= (x/x) X 100.
Then finally gain% = 100.
Gurpreet.singh said:
6 years ago
Let's suppose C.P=100 then If I double it S.P would become 200.
Profit would be 200-100=100, it's not tripled, the question is bit confusing.
Profit would be 200-100=100, it's not tripled, the question is bit confusing.
V.krishna (v.k) said:
6 years ago
Given S.P is doubled,
Let us think S.P = 100 and profit = 50.
Now S.P is doubled = 200.
C.P = 50 as C.P = S.P-Profit.
Profit = S.P - C.P.
=200 - 50.
= 150.
Profit is tripled as (50)(3) = 150.
Let us think S.P = 100 and profit = 50.
Now S.P is doubled = 200.
C.P = 50 as C.P = S.P-Profit.
Profit = S.P - C.P.
=200 - 50.
= 150.
Profit is tripled as (50)(3) = 150.
PGN said:
6 years ago
P=s.p-c.p.
According to condition,
3P= 2(s.p)-c.p,
Solve the equations simultaneously.
We get.
s.p=2P.
c.p=P.
Now
P%=(s.p-c.p/cp) * 100.
Put values, we get;
P%=100.
According to condition,
3P= 2(s.p)-c.p,
Solve the equations simultaneously.
We get.
s.p=2P.
c.p=P.
Now
P%=(s.p-c.p/cp) * 100.
Put values, we get;
P%=100.
MARISELVAM M said:
5 years ago
I can't understand the second step. Can you please explain it?
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