Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
303 comments Page 27 of 31.
Harish Raj said:
1 decade ago
I don't think there should be necessary for explanation for this sum. It is just the common sense we need to apply. Coming to the Question.
If selling price is doubled, the profit triples. Find the profit percent.
I think we can answer this question without considering the 3 times of profit. I mean to read the question like this -- (If selling price is doubled, Find the profit percent.)
It is obviously 100%, right?
If selling price is doubled, the profit triples. Find the profit percent.
I think we can answer this question without considering the 3 times of profit. I mean to read the question like this -- (If selling price is doubled, Find the profit percent.)
It is obviously 100%, right?
Ravi teja said:
1 decade ago
Consider C.p=x, S.P=2x, Profit=3x
gain=S.p-C.P=2x-x=x
so gain=x,
profit=(gain/C.P*100)=(x/x*100)
profit=100%....
simple man....
gain=S.p-C.P=2x-x=x
so gain=x,
profit=(gain/C.P*100)=(x/x*100)
profit=100%....
simple man....
Samy said:
1 decade ago
Balaji answer is nice thanks to you.
Ravi said:
1 decade ago
Thanks @balaji
Shree said:
1 decade ago
Raj answer is so simple:).
Ramkumar said:
1 decade ago
Thanks Satish. Its really simple.
Hamzah Bhatti said:
1 decade ago
Let Cost Price Be X AND Selling Price be Y And Profit for this is Z, THEN BY given Condition
((y-x)/x)*100=Z -------------- (1)
Similarly By Given Condition
((2y-x)/x)*100 =3Z Or Z = ((2Y-X)/3X)*100 -------- (2)
Both eqn 1 and 2 are equal equating these two eqn gives
3(y-x) =2y-x
y=2x
Put this value in eqn 1 and get z = 100.
((y-x)/x)*100=Z -------------- (1)
Similarly By Given Condition
((2y-x)/x)*100 =3Z Or Z = ((2Y-X)/3X)*100 -------- (2)
Both eqn 1 and 2 are equal equating these two eqn gives
3(y-x) =2y-x
y=2x
Put this value in eqn 1 and get z = 100.
Sindhu said:
1 decade ago
See balaji explaination. Its very clear.
Tushar Vaibhav said:
1 decade ago
PROFIT = 3(Y-X)= (2Y-X)
= 3Y-3X-2Y+X
= 1Y-2X
(i.e)Y=2X : Profit = (Y-X)(i.e) =(2x-x)=Rs.x
Profit% = C.P/profitX100= X/X*100=100%.
FROM HERE EXPLAIN CLEARLY.
= 3Y-3X-2Y+X
= 1Y-2X
(i.e)Y=2X : Profit = (Y-X)(i.e) =(2x-x)=Rs.x
Profit% = C.P/profitX100= X/X*100=100%.
FROM HERE EXPLAIN CLEARLY.
Narayanan said:
1 decade ago
Ya..balaji's explanation is clear Profit= y-x___________(1)
From the data given, if selling price doubles, profit will be tribled. So that
From(1), we can write
Profit = y-x, here from the data given if y doubles profit will be tribled. so we can write in place of profit we can write y-x
3(y-x) = 2y-x.
From the data given, if selling price doubles, profit will be tribled. So that
From(1), we can write
Profit = y-x, here from the data given if y doubles profit will be tribled. so we can write in place of profit we can write y-x
3(y-x) = 2y-x.
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