Aptitude - Profit and Loss - Discussion

Assume C.P = x.
//Then selling price is double.

Means S.P = 2x.
Profit = (S.P - C.P).
So profit = 2x-x = x.

%Profit = prifit*100/C.P.
= x*100/x.
= 100.

Give me inform what is the process in this question?

SP = x;
CP = y;
p = (x-y) * 100 / y;
SP' = 2x;
P' = 3*P;

=> (2x-y) * 100 / y = 3 * (x-y) * 100 / y;
=> x = 2 * y;
=> SP = 2 * CP;
=> P = 100%;
=> Profit Percent = 100%.

We know that SP = CP + profit........1.
Now given 2 SP = CP + 3 profit........2.

ON solving these equation we get that,
S.P = 2 profit.

Now in equation SP-CP/CP*100.
Answer is 100%.

No need that much solution.

Let CP = 1 Rs.
Then SP = 2 rs (because double).

Leave profit is triple. no need to take,
That's why profit % is 100% (because double).

Really I am confusing about this question. Because Q)If selling price is doubled, the profit triples. Find the profit percent.

SP double means we always determined SP on CP. So obviously CP = x and SP = 2x.
And profit always depend upon diff btw SP and CP. So Profit = x.

But according to question profit = 3X.

Then profit% = (profit/CP)*100.

If profit = X then P%= 100%.

But as per question p=3X so profit = (3x/x)*100 = 300%.

How is it possible. Please clarify my doubt?

Let 1st S.P = 100, profit - 1x, and 2nd S.P = 200,
If profit is tripled then it is 3x.

Therefore 3x-1x= 2x,
x = 200/2.
x = 100.

Let, profit = x.
C.P = 100.

Selling Price = 100+x.
We know that:(S.P-C.P) = Profit.

According to Q,

2(100+x)-100= 3*x.
200+2x-100 = 3x.
3x-2x = 200-100.
x = 100.

Profit= 100%.

Don't you people feel that the ques is not clear. If they are asking for the profit% shouldn't we find out the new profit%?

Assume S.P as 10.
Profit as 5,

(3 times of profit)/(2SP -3profit) *100 = 15/(20-15)*100.
= 30%.

C.P = 100.
S.P = 200(i.e S.P doubled).

Profit = S.P - C.P.
=>200-100 = 100.

Profit % = (profit*100)/C.P.
= (100*100)/100.
= 100.