Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) 
y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % = |
 |
x | x 100 |  % = 100% |
| x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
304 comments Page 21 of 31.
Sapah said:
1 decade ago
Let 100rs be the sales cost (cp + profit).
By selling it for 200rs profit triples (cp + 3*profit).
200-100 = 2*profit.
Profit = 50.
Therefore cp = 50.
Profit % = (sales-cp)/cp% = 1000.
By selling it for 200rs profit triples (cp + 3*profit).
200-100 = 2*profit.
Profit = 50.
Therefore cp = 50.
Profit % = (sales-cp)/cp% = 1000.
Awdhesh said:
1 decade ago
s-c=p....1.
Now 2s-c = 3p....2.
Solve this.
s = 2p....3.
So c=p.....4.
Now as asked that when sp is 2 times then calculate pf percentage.
So (2s-c/c)*100 = pf percent.
So put value in terms of p.
2s = 4p.....from....3.
So (4p-p)/p)*100 = pf percentage.
So pf percentage 300.
Now 2s-c = 3p....2.
Solve this.
s = 2p....3.
So c=p.....4.
Now as asked that when sp is 2 times then calculate pf percentage.
So (2s-c/c)*100 = pf percent.
So put value in terms of p.
2s = 4p.....from....3.
So (4p-p)/p)*100 = pf percentage.
So pf percentage 300.
Sonu nayak said:
1 decade ago
C.P-S.P profit x y(y-x).
x 2y(2y-x) according to question. The profit 3 times increased if S.P became doubled this means profit has increase from earlier (profit) three times.
This implies 3 times of of old profit must be equal to new profit.
= 3(y-x) = 2y-x.
By solve y = 2x.
And profit is y-x/x*100 = 2x-x/x*100 = 100%.
x 2y(2y-x) according to question. The profit 3 times increased if S.P became doubled this means profit has increase from earlier (profit) three times.
This implies 3 times of of old profit must be equal to new profit.
= 3(y-x) = 2y-x.
By solve y = 2x.
And profit is y-x/x*100 = 2x-x/x*100 = 100%.
Vinay said:
1 decade ago
Let C.P. --> x then.
S.P. --> 2x.
Profit = S.P.-C.P. = 2x-x = x.
Profit% = Profit\C.P.*100 = 100%.
S.P. --> 2x.
Profit = S.P.-C.P. = 2x-x = x.
Profit% = Profit\C.P.*100 = 100%.
Sara said:
1 decade ago
Hai friends.
Profit means selling price > cost price.
Profit% = (profit/cost price)*100.
Selling price doubles. So we take 2S>1.
So actual cost price is single. So S>2.
Now from profit % formula = ((2S/S)/100)% = 100%.
Profit means selling price > cost price.
Profit% = (profit/cost price)*100.
Selling price doubles. So we take 2S>1.
So actual cost price is single. So S>2.
Now from profit % formula = ((2S/S)/100)% = 100%.
Akhila said:
1 decade ago
As given in the problem. SP-CP = Profit right.
Consider that SP-CP = (y-x).
Now SP should be double that is 2y-x.
And CP should be triple that is 3(y-x).
That is 2y-x = 3(y-x).
By solving this will get the profit.
Consider that SP-CP = (y-x).
Now SP should be double that is 2y-x.
And CP should be triple that is 3(y-x).
That is 2y-x = 3(y-x).
By solving this will get the profit.
MRIGANSH MATHUR said:
1 decade ago
Its just this that you can compare only similar things. Like profit with profit.
So, in this case when profit is thrice so SP is doubled.
So when it is equated.
3(y - x) = (2y - x)y = 2x.
In this profit as we know is (y-x) which is thrice.
So when we equate this we equate it with the profit at this time when it is thrice ok.
So the profit at this time would be SP-CP but here SP is twice at q so that is why 2y-x is there.
So, in this case when profit is thrice so SP is doubled.
So when it is equated.
3(y - x) = (2y - x)y = 2x.
In this profit as we know is (y-x) which is thrice.
So when we equate this we equate it with the profit at this time when it is thrice ok.
So the profit at this time would be SP-CP but here SP is twice at q so that is why 2y-x is there.
DEBLINA DUTTA said:
1 decade ago
Let, CP: 'X' and SP: 'Y' and profit : 'P'.
Then, P= (Y-X) / X ----------- (1).
Now, new SP= '2Y' and new profit : '3P'.
Then, 3P= (2Y-X) / X -------------- (2).
Put the value of 'P' from equation number (1).
So, (2Y-X) / X = (3Y-3X) / X.
Or, 2XY-X^2 = 3XY-3X^2.
Or, Y = 2X.
Put the value of 'Y' in eqn no. (1).
So, (2X-X) / X = P = 1*100 =100.
(ie) 100%.
Then, P= (Y-X) / X ----------- (1).
Now, new SP= '2Y' and new profit : '3P'.
Then, 3P= (2Y-X) / X -------------- (2).
Put the value of 'P' from equation number (1).
So, (2Y-X) / X = (3Y-3X) / X.
Or, 2XY-X^2 = 3XY-3X^2.
Or, Y = 2X.
Put the value of 'Y' in eqn no. (1).
So, (2X-X) / X = P = 1*100 =100.
(ie) 100%.
Kehkashaa dubey said:
1 decade ago
I am confused. How would I do it without using x and y?
Could somebody provide me with a logic? When I did it logically it came our to be 200%.
Could somebody provide me with a logic? When I did it logically it came our to be 200%.
Divya said:
1 decade ago
CP = x, SP = 2x.
Profit = SP-CP = 2x-x = x.
%profit = (profit/CP)*100.
= x/x*100.
= 100.
Profit = SP-CP = 2x-x = x.
%profit = (profit/CP)*100.
= x/x*100.
= 100.
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