Aptitude - Profit and Loss - Discussion

We know,

p%= ( sp - cp ) / cp * 100-----(1)
So we have sp - cp = ( p *cp )/100-------(2)
we are given that profit is tripled and sp is doubled

So we have profit % 3p.
from one replace p by 3p and sp by 2 sp
we arrive at,
3p=(2sp - cp)/cp *100.
so now
(3p*cp )/100 =2sp - cp.
3(p *cp)/100 =2sp -cp.
we can replace p*cp/100 with (sp-cp) -----from (2).
so 3(sp-cp)=2sp - cp.
3sp-3cp=2sp-cp.
sp=2cp -(3).
so now we have from 1.
p%=2cp-cp/cp *100 (replace sp=2cp).
p%=100.

let profit=p.
s.p.=x.
c.p.=y.

Profit=s.p.-c.p.=x-y
Now profit triple and s.p. double means,
3p=2x-y
but p=x-y ,put in equation
3(x-y)=2x-y
x=2y , we got
profit p=x-y,
p=2y-y=y (x=2y).

Now, profit %= (gain*100)/c.p.
profit %=(y*100)/y (gain p=y, c.p.=y).
profit%=100%.

Well done @Balaji.

@All.

For example
SP=100
CP=50
Profit=100-50=50

Now SP1=2(100)
CP=50
Profit1=200-50=150

So in this case, if selling price increased by double sp1=2*sp then profit1=3*profit... it seems final question requires detailed information. Like total extra profit 150-50=100 which is 100% of selling price.

How about doing this question like this?

Let CP be Rs 100,
then by question SP =200,
then profit percent is;
(SP-CP)*100÷CP,
so ( 200-100)*100÷ 100,
=100.

So required answer is 100, hope I am right please suggest me if I am wrong.

Is it 100% of the original price or of the doubled price.

Lets say, c.p.= x and,
s.p.= y initially.
according to formula,
s.p. - c.p. = profit,

So, (y-x) = profit at initial. ....[1]
Now, s.p. is doubled, it becomes 2y
The profit is tripled, it becomes 3(y-x).
But c.p. remains same, it is x.
Again using formula,
s.p. - c.p. = profit.
2y - x = 3(y-x).
3x-x = 3y-2y
2x = y (s.p.)

The question have asked how much profit percent after condition applied
So, we have to consider initial c.p. (x) and final s.p. (2x) (from above solution)
Profit= s.p. - c. p.
= 2x - x
= x.

Profit % = (profit/c.p.)*100
=x/x *100
=100%.

We know that profit% = (gainx100÷CP)......"i"
SP-CP=profit......."ii"
Also, 2SP-CP=3profit......."iii"

Therefore by subtracting "ii" from"iii"
We get SP=2profit.
Again we use SP-CP=profit.
Put value SP=2profit in it....."iiii"
We get CP=profit.
Now let CP be 100.
So profit/gain =100.

Using equation %profit=(gain*100÷CP).
We get profit% =100.

How is it possible?

Let c.p = x,
s.p=2x,
p.f = 3x,
p.f=s.p-c.p.
3x=2x-x,
3x=x,
p.f = s.p-c.p/c.p*100,
=x/x*100,
=100.