Aptitude - Profit and Loss - Discussion

Let c.p=x
s.p=2x

Profit = s.p - c.p
Profit = 2x - x = x
Profit % = x*100/x = 100%

= S.P - C.P = PROFIT/100%

= 2X- 3X =1X/100%

= X = 1/100
=100%.

Let s.p. = y and c.p. = x
now current profit is (y-x)
and the profit when the s.p. is doubled is (2y-x)
now according to the equation
(2y-x)/3 = (y-x) bcaz new profit is thrice a current profit
solving equation we get y=2x
when s.p. is doubled as c.p.
so profit = (y-x)/x * 100 = (2x-x)/x * 100 = 100%

If we assume current SP to be Rs.100/- and then profit as x. Then,
SP Profit
100 x
200 3x

Therefore, 300x+200x=600x
Therefore, x=100. I guess this is an easier approach.

First of all, in the problem they had given that if selling price doubles, profit will be tribled.

Actually we have the formulae that
profit = selling price - cost price

Let the selling price be y and cost price be x

From formulae above profit= s.p.-c.p.

Profit= y-x___________(1)

From the data given, if selling price doubles, profit will be tribled. so that

From(1), we can write

profit=y-x, here from the data given if y doubles profit will be tribled. so we can write in place of profit we can write y-x

3(y-x) = 2y-x
y=2x
profit from (1)
profit=2x-x
= x

Then we have to calcute profit percentage, so we have formulae for profit percentage
Profit%= (profit/cost price)*100
= (x/x)*100

Profit% =100%.

Let SP= 10 Rs.

If it is doubled den SP =20rs,

So profit will be 10 Rs nothing but 100% profit.

profit per= ((s.p-c.p)/c.p)*100
c.p=x
s.p=2x
profit per = ((2x-x)/x)*100
=100
simple

3(y - x) = (2y - x) In this eqn how you subtract x from 2y?

I can not undestand pls explain.

I am also not able to understand how you substract x from 2y.. please explain... plz

Balaji explained well thank you very much.