Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 3)
3.
If selling price is doubled, the profit triples. Find the profit percent.
Answer: Option
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
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x | x 100 | ![]() |
x |
Video Explanation: https://youtu.be/dPzF10mGsWE
Discussion:
304 comments Page 17 of 31.
Elentia Chhangte said:
9 years ago
Cp = x, sp = 2x, profit = 3x.
Profit = sp - cp.
= 3x - 2x = x.
Profit % = profit/cp * 100.
= x/x * 100,
= 100%.
Profit = sp - cp.
= 3x - 2x = x.
Profit % = profit/cp * 100.
= x/x * 100,
= 100%.
Jyothi said:
9 years ago
P = sp -cp
2x -x = x.
P% = x/x * 100%
100%.
2x -x = x.
P% = x/x * 100%
100%.
Jishu said:
9 years ago
profit = sp - cp.
2x - x = x.
p% = x/x * 100%.
= 100%.
2x - x = x.
p% = x/x * 100%.
= 100%.
Rishabh said:
9 years ago
First of all, in the problem, they had given that if selling price doubles, profit will be tripled.
Actually, we have the formulae that profit = selling price - cost price
Let the selling price be y and cost price be x.
From formulae above profit= s.p.-c.p.
Profit= y-x___________(1)
From the data given, if selling price doubles, profit will be tripled. so that
From(1), we can write
Profit=y-x, here from the data given if y doubles profit will be tribled. so we can write in place of profit we can write y-x.
3(y-x) = 2y-x.
y = 2x.
profit from (1)
profit =2x-x,
= x.
Then we have to calculate profit percentage, so we have formulae for profit percentage
Profit%= (profit/cost price)*100.
= (x/x)*100.
Profit% =100%.
Actually, we have the formulae that profit = selling price - cost price
Let the selling price be y and cost price be x.
From formulae above profit= s.p.-c.p.
Profit= y-x___________(1)
From the data given, if selling price doubles, profit will be tripled. so that
From(1), we can write
Profit=y-x, here from the data given if y doubles profit will be tribled. so we can write in place of profit we can write y-x.
3(y-x) = 2y-x.
y = 2x.
profit from (1)
profit =2x-x,
= x.
Then we have to calculate profit percentage, so we have formulae for profit percentage
Profit%= (profit/cost price)*100.
= (x/x)*100.
Profit% =100%.
DAVID SAMUEL said:
8 years ago
P = S.P-C.P...............1
3P = 2S.P-C.P...........2
BY SOLVING 1 AND 2 WE GET.
S.P=2 C.P..........3.
WE KNOW (P=S.P-C.P)...PUT 3 IN THIS;
WE GET,
P=C.P........4.
PUT 4 IN FORMULA OF P%.
we GET P%=C.PX100/C.P.
P% = 100.
VERY SIMPLE.
3P = 2S.P-C.P...........2
BY SOLVING 1 AND 2 WE GET.
S.P=2 C.P..........3.
WE KNOW (P=S.P-C.P)...PUT 3 IN THIS;
WE GET,
P=C.P........4.
PUT 4 IN FORMULA OF P%.
we GET P%=C.PX100/C.P.
P% = 100.
VERY SIMPLE.
Nibedita Banerjee said:
8 years ago
LET,
C.P= 100.
PROFIT= x.
THEREFORE , S.P =100 + x.
AS PER THE QUESTION,
2 * S.P- C.P = 3 * PROFIT.
2(100+x)-100 = 3x
or, 200+2x-100 = 3x.
or, x = 100.
C.P= 100.
PROFIT= x.
THEREFORE , S.P =100 + x.
AS PER THE QUESTION,
2 * S.P- C.P = 3 * PROFIT.
2(100+x)-100 = 3x
or, 200+2x-100 = 3x.
or, x = 100.
Mohd Murtaza Ali Khan said:
8 years ago
Very short method.
Let CP = x
Sp is double = 2x
Gain=sp-cp = x
Gain = (100 * gain/CP),
= (100 * x/x),
= 100.
Let CP = x
Sp is double = 2x
Gain=sp-cp = x
Gain = (100 * gain/CP),
= (100 * x/x),
= 100.
Pradeep said:
8 years ago
@Mohd Murtaza.
Triple profit is missing in your explanation.
Triple profit is missing in your explanation.
Sharath said:
8 years ago
Profit = sp-cp......1.
New sp = 2sp(given)
New profit = 3profit(given)
New profit =new sp - cp.
i.e 3profit= 2sp-cp.......2
2 divided by 1.
3=(2sp-cp)/(sp - cp).
After simplification we get sp= 2cp.
Substitute this in profit equation.
Profit = 2cp - cp.
=> profit = cp.
%profit= (profit/cp) * 100.
=>(cp/cp) * 100.
Hence 100%.
New sp = 2sp(given)
New profit = 3profit(given)
New profit =new sp - cp.
i.e 3profit= 2sp-cp.......2
2 divided by 1.
3=(2sp-cp)/(sp - cp).
After simplification we get sp= 2cp.
Substitute this in profit equation.
Profit = 2cp - cp.
=> profit = cp.
%profit= (profit/cp) * 100.
=>(cp/cp) * 100.
Hence 100%.
Pranitha said:
8 years ago
I can't understand. Why we are substituting 3(y-x) = (2y-x)?
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