Aptitude - Profit and Loss - Discussion

Is it 100% of the original price or of the doubled price.

How about doing this question like this?

Let CP be Rs 100,
then by question SP =200,
then profit percent is;
(SP-CP)*100÷CP,
so ( 200-100)*100÷ 100,
=100.

So required answer is 100, hope I am right please suggest me if I am wrong.

@All.

For example
SP=100
CP=50
Profit=100-50=50

Now SP1=2(100)
CP=50
Profit1=200-50=150

So in this case, if selling price increased by double sp1=2*sp then profit1=3*profit... it seems final question requires detailed information. Like total extra profit 150-50=100 which is 100% of selling price.

Well done @Balaji.

let profit=p.
s.p.=x.
c.p.=y.

Profit=s.p.-c.p.=x-y
Now profit triple and s.p. double means,
3p=2x-y
but p=x-y ,put in equation
3(x-y)=2x-y
x=2y , we got
profit p=x-y,
p=2y-y=y (x=2y).

Now, profit %= (gain*100)/c.p.
profit %=(y*100)/y (gain p=y, c.p.=y).
profit%=100%.

We know,

p%= ( sp - cp ) / cp * 100-----(1)
So we have sp - cp = ( p *cp )/100-------(2)
we are given that profit is tripled and sp is doubled

So we have profit % 3p.
from one replace p by 3p and sp by 2 sp
we arrive at,
3p=(2sp - cp)/cp *100.
so now
(3p*cp )/100 =2sp - cp.
3(p *cp)/100 =2sp -cp.
we can replace p*cp/100 with (sp-cp) -----from (2).
so 3(sp-cp)=2sp - cp.
3sp-3cp=2sp-cp.
sp=2cp -(3).
so now we have from 1.
p%=2cp-cp/cp *100 (replace sp=2cp).
p%=100.

Here p=s.p-c.p,
3p=2s.p-c.p,
3(s.p-cp)=2s.p-c.p ---->(p=s.p-c.p),
s.p = 2c.p,
p% = s.p-c.p/c.p * 100,
= 2c.p-c.p/c.p *100,
= 100%.

3(y - x) = (2y - x) this equation is wrong given in answer.

The equation must be 3(y-x)=2y.

Let, profit percentage=x%.
if c.p is 100 Rs then s.p (100+x).
now we get from the conditions,
2(100+x)-100 = 3x.
or,200+2x-100 = 3x.
or,x = 100.

profit = sp - cp.
3 profit = 2 sp - cp.
profit = cp.
profit % = profit / cp * 100 = cp / cp * 100 = 100%.