Aptitude - Profit and Loss - Discussion

Thank you so much, well explained @Preitee Ranjan.

P=392-x.
%=p/cp*100.
22.5=(392-x)/x*100.
22.5x=392-x*100,
22.5x=39200-100x,
22.5x+100x=39200,
122.5x=39200,
x=39200/122.5,
x=392000/1225,
x=320-->cp.

P=392-x,
P=392-320,
P=72 Rs.

@Jyothi.

Thank you.

Thank you all for explaining it.

In this question we have to find profit value,

We all know that profit =SP - CP.

Here s. P=Rs.392(which is given in the question)
Now we have to find c. P value then only we will get the profit value
By using this formula C. P=100/100+gain %*s.p(given in important formulas)
Then c. P=100/100+22.5*392(here gain% and s. P values are given in the question)
C.p=100/122.5*392

By simplifying this we will get CP value,
Therefore c. P=Rs. 320,
Now substitute the SP and CP values in profit formula.
Profit = SP- CP.
Profit =Rs. (392-320),
Profit =Rs. 72.

Given G=22.5% on cost price.

Profit = ?
Profit =SP - CP.

CP is unknown.
Given SP = 392
SP = [(100+G%)*cp]/100,
CP = (SP*100)/(100+G%),
CP = (392*100)/(100+22.5),
CP = 320,
Profit = SP - CP.
Profit = 392 - 320,
Profit = 72.

This is just one step problem;
392/122.5 = 3.2,
3.2*22.5 = 72.

cp =100 profit =22.5
sp =100+22.5 =122.5.

122.5 -------------> 22.5
392 --------------> x.

(392|*22.5)/122.5 = 72.

Thanks @Rajadurai.

Thanks @Preitee.