Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 31)
31.
Two, trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:
Answer: Option
Explanation:
Let us name the trains as A and B. Then,
(A's speed) : (B's speed) = b : a = 16 : 9 = 4 : 3.
Discussion:
109 comments Page 6 of 11.
Yadu Krishnan said:
7 years ago
Here we need to find the ratio of the speed of the trains for which trains have travelled.
Distance D is same for both. So the ratio of speed,
=> S1:S2,
=> D/a:D/b,
=>1/a:1/b
=>b:a.
Distance D is same for both. So the ratio of speed,
=> S1:S2,
=> D/a:D/b,
=>1/a:1/b
=>b:a.
Karthik said:
1 decade ago
In this question we need to calculate the ratio only after the trains have met each other. For overall distance the ration will be a:b. For distance after each trains met will be in square roots.
Vrushabh shivle said:
12 months ago
Here we can use the ratio method:
Train 1 ( Howrah to Patna) = A.
Train 2 ( Patna to Howrah) = B/
Ratio of speed = √speed of A/ √speed of B
= √16/√9.
= 4/3.
That is the answer is 4 : 3.
Train 1 ( Howrah to Patna) = A.
Train 2 ( Patna to Howrah) = B/
Ratio of speed = √speed of A/ √speed of B
= √16/√9.
= 4/3.
That is the answer is 4 : 3.
(2)
Karunakaran said:
1 decade ago
Let distance = x, a as speed of train a & b as speed of train b
9 x a = x
16 x b= x
9a = 16b
a/b = 16/9, simplify this with square root both up & down we get 4/3 & ratio 4:3.
9 x a = x
16 x b= x
9a = 16b
a/b = 16/9, simplify this with square root both up & down we get 4/3 & ratio 4:3.
Rohit said:
1 decade ago
Read the question carefully, it is given that after they met at particular time, they take further 9 hrs and 16 hrs to reach THEIR destination. Try to solve that way, then you will get 4:3.
Yogesh said:
7 years ago
The initial answers were lengthy.
Now since both are departing at same time,
1 step d1/d2=v1*t/v2*t=v1/v2,
2nd step d1/d2=v2*16/v1*9,
And on equating both we get the required solution.
Now since both are departing at same time,
1 step d1/d2=v1*t/v2*t=v1/v2,
2nd step d1/d2=v2*16/v1*9,
And on equating both we get the required solution.
Ragho said:
1 decade ago
@Bhargav. Buddy see here we have to calculate the ratio and the ratio of two quantities will be unit less, so here we don't need any units. I hope you will get this explanation.
Arun Kumar said:
1 decade ago
The distance cover by both train = x.
The speed of both trains are s1 and s2.
Then,
s1=x/9 --- (1).
s2=x/16 --- (2).
Then,
s1/s2= x/9/x/16.
s1/s2= 16/9.
s1:s2= 16:9.
The speed of both trains are s1 and s2.
Then,
s1=x/9 --- (1).
s2=x/16 --- (2).
Then,
s1/s2= x/9/x/16.
s1/s2= 16/9.
s1:s2= 16:9.
Mr.AJ said:
1 decade ago
@Abhishek.
Dude it is mentioned after they meet. At this point both trains are travelling with different speeds so they did not meet at mid point.
Hope you are clear.
Dude it is mentioned after they meet. At this point both trains are travelling with different speeds so they did not meet at mid point.
Hope you are clear.
Kiran.p said:
2 decades ago
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