Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 25)
25.
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
Answer: Option
Explanation:
Let the speed of the second train be x km/hr.
| Relative speed | = (x + 50) km/hr | |||||||
|
||||||||
|
![]](/_files/images/aptitude/1-sym-cbracket-h1.gif)
Distance covered = (108 + 112) = 220 m.
 |
220 | = 6 | ||
|
250 + 5x = 660
x = 82 km/hr.
Discussion:
77 comments Page 4 of 8.
MAHI said:
5 years ago
Here, time is in seconds & distance is in meters that's why we have to convert the speed into m/sec. Initially assume that X is in km/hr. SO we have to convert the speed in m/sec as all parameters is in meter & seconds. After solving where get the value of x in km/hr,
Swati hande said:
5 years ago
Thanks all for explaining.
Kajal said:
5 years ago
Why have we assumed x in km/he why not in m/s?
Please, someone, explain it.
Please, someone, explain it.
Shubham said:
5 years ago
Thanks @Mahi.
Deepa Singh said:
1 decade ago
Please solve this part clearly 220/(5x+250)/18=6
Rakshikasaravanan said:
5 years ago
First train speed 50sec.
Second train speed?
S = l1 + l2/t1 + t2.
Relative speed = x + 50s.
X + 50s = 108+112/6+t2.
X + 50s =792/6.
6x + 300=792.
6x = 792-300.
6x = 492.
X = 492/6.
X = 82.
Second train speed?
S = l1 + l2/t1 + t2.
Relative speed = x + 50s.
X + 50s = 108+112/6+t2.
X + 50s =792/6.
6x + 300=792.
6x = 792-300.
6x = 492.
X = 492/6.
X = 82.
Ramesh said:
1 decade ago
(220)m
----------------- =6 sec.
((250+5x)/18)m/s
here,m and s are cancelled so x km/hr.
----------------- =6 sec.
((250+5x)/18)m/s
here,m and s are cancelled so x km/hr.
Priyavel said:
1 decade ago
Hi.
I can't get it clearly. Please anyone explain it.
I can't get it clearly. Please anyone explain it.
Nagesh said:
3 years ago
6 = 220 then,
36 = (x+50)*10.
After cross multiple;
6*22 = X + 50.
X = 82.
36 = (x+50)*10.
After cross multiple;
6*22 = X + 50.
X = 82.
GAISINREI said:
3 years ago
First convert km/hr in m/secs,
x= 410/18 m/secs.
for km/hr.
41O/18 * 18/5 = 82km/hr.
x= 410/18 m/secs.
for km/hr.
41O/18 * 18/5 = 82km/hr.
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