Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 24)
24.
Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
Answer: Option
Explanation:
| Speed of the first train = |  |
120 |  |
m/sec = 12 m/sec. |
| 10 |
| Speed of the second train = | |
120 | |
m/sec = 8 m/sec. |
| 15 |
Relative speed = (12 + 8) = 20 m/sec.
 Required time = |
 |
(120 + 120) | ![]](/_files/images/aptitude/1-sym-cbracket-h1.gif) |
sec = 12 sec. |
| 20 |
Discussion:
22 comments Page 3 of 3.
Nikhil said:
5 years ago
Speed of T1 = 120/10 = 12m/s.
Speed of T2 = 120/15 = 8m/s.
Time taken to cross each other = D/S = (120 + 120)/12 + 8 = 12 secs.
Speed of T2 = 120/15 = 8m/s.
Time taken to cross each other = D/S = (120 + 120)/12 + 8 = 12 secs.
(3)
AUNRAJ JAGTAP said:
7 months ago
Very nice, Thanks for explaining the answer.
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