Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 24)
24.
Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
Answer: Option
Explanation:
| Speed of the first train = |  |
120 |  |
m/sec = 12 m/sec. |
| 10 |
| Speed of the second train = | |
120 | |
m/sec = 8 m/sec. |
| 15 |
Relative speed = (12 + 8) = 20 m/sec.
 Required time = |
 |
(120 + 120) | ![]](/_files/images/aptitude/1-sym-cbracket-h1.gif) |
sec = 12 sec. |
| 20 |
Discussion:
22 comments Page 2 of 3.
Priya said:
8 years ago
Why are we not calculate this way,
s = 120+120/10+15,
= 9.6 m/s.
Correct me if I am wrong.
s = 120+120/10+15,
= 9.6 m/s.
Correct me if I am wrong.
(1)
Sarika said:
2 decades ago
Two trains running in opposite directions means they come towords each other.
Shweta said:
6 years ago
Why didn't we take (15+10) directly as speed like we add in other questions.
(1)
Akhilesh said:
9 years ago
Anyone can explain this problem? because I'm not understand this problem.
Sam said:
6 years ago
This problem should tell us,two trains are coming from opposite sid.
(1)
Siddharth Kapoor said:
2 decades ago
How can 2 trains running in opposite direction cross each other!!!!
Diya said:
1 decade ago
I am not clear with this problem. Can anyone please explain.
AUNRAJ JAGTAP said:
7 months ago
Very nice, Thanks for explaining the answer.
Shree said:
7 years ago
Thank you all for explaining the answer.
Sudharsan madurai said:
1 decade ago
Average of 10+15 = 12.5.
Almost = 12.
Almost = 12.
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