Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 17)
17.
A train 800 metres long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is:
130
360
500
540
Answer: Option
Explanation:

Speed = ( 78 x 5 ( m/sec = ( 65 ( m/sec.
18 3

Time = 1 minute = 60 seconds.

Let the length of the tunnel be x metres.

Then, ( 800 + x ( = 65
60 3

=> 3(800 + x) = 3900

=> x = 500.

Discussion:
52 comments Page 4 of 6.

Dinesh said:   9 years ago
If there will be 75 km/h then what will be the answer?

Jay said:   8 years ago
Speed=78 km/hr
=78 x 5/18 = 65/3 m/sec
Time = i min = 60 sec
Let the length of he tunnel be x metres
but here already given 800 metres
Therefore d=s x t

So,
800x=65/3 x 60
800x= 1300
x= 1300 - 800
x= 500.

Asmamaw said:   8 years ago
How the number 5/18 came? please clarify me.

Sahdev said:   8 years ago
3(800+x) =3900 = 1500.

Then x = 500?

Naman said:   8 years ago
What if we turn the speed into m/s first, like.

78 x (5/18)=> 65/3 => 15,
then use formula D = S*T.
then we get,
D+800 = 15 * 60.
D+800 = 900,
D = 100,

Is this wrong ?
why 2 different answer?

Sarang said:   7 years ago
Distance =speed * time,
D=78km/h*1minute,
D=78*5/18*60.
D=78*.277*60.
D=21.6*60= 1300-800= 500.

Sasinrit said:   7 years ago
Speed =78000/3600=1300/min.

Length of tunnel=1300-800=500.
(1)

Arushi said:   6 years ago
I am not getting, how come 5/18? Please, someone explain me.

Roobha said:   6 years ago
1km = 1000m,
1hr = 3600sec.

Convert,
Km/hr=m/sec.
= 1000/3600m/sec,
= 5/18m/sec.

Yt prasad said:   6 years ago
65/3 * 60 = 65 * 20 = 1300 - 800 = 500.
(2)


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