Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 17)
17.
A train 800 metres long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is:
130
360
500
540
Answer: Option
Explanation:

Speed = ( 78 x 5 ( m/sec = ( 65 ( m/sec.
18 3

Time = 1 minute = 60 seconds.

Let the length of the tunnel be x metres.

Then, ( 800 + x ( = 65
60 3

=> 3(800 + x) = 3900

=> x = 500.

Discussion:
52 comments Page 1 of 6.

Rishika V said:   2 months ago
@Agggy.

we add the length of the the train and tunnel because the train is said to have crossed the tunnel if and only if its entire part including the the very last end of it leaves the tunnel.

so if the train has crossed the tunnel in 1min then it would have covered the entire length of the tunnel and a certain distance outside the tunnel (the distance covered by the train until the very last end of the train leaves the tunnel).

So,
that 'certain distance' = length of the train.
.A______x______.B.______800______.C.

where x is the length of the tunnel and the length of the train is 800 m.
the total distance covered by the train is x + 800.

DISTANCE = X+800 m
SPEED = 78 km/hr
TIME = 60sec.

convert speed from km/hr to m/s.
SPEED = 78x1000/60 x 60.
SPEED = 65m/s.

distance /speed = time.
X + 800/65 = 60,
X + 800 = 60x65/3,
X + 800 = 3900/3,
X + 800 = 1300,
X = 1300 - 800,
X = 500.

Agggy said:   3 months ago
Why we are adding the length of train and length of tunnel? Anyone please explain to me.

Bunny said:   5 months ago
Speed = 78 * 1000/60 = 1300.
Total length = length of tunnel + length of train,
1300 = length of tunnel + 800.
Length of the train = 1300-800 = 500.
(1)

Abdul azees said:   3 years ago
Easy way

Distance = 800 meter,
Speed = 78 km/hr,
Time =1 min,
Need to find 800+x,
speed = 78km/hr~1300 meter/minute,
800+x = 1300 *1 as per (D = S * T formula),
x = 1300 - 800.
x = 500 meters.
That's all.
(6)

Somil kumar bhadula said:   3 years ago
3(800+x) = 1900
2400+3x = 1900
3x = 2400-1900,
3x = 500.
I understand the thing. But where the 3x goes?

Can somebody tell me?

Joel said:   3 years ago
@Pradnyashree.

How is 3900-2400 =500?

It's 1500. Can anyone explain that?
(2)

Khushi said:   4 years ago
@All.

Please correct me, if my calculation is wrong.

If we convert 78 km/hr into m/s.
So,
78 * 5/18.
390/18.
21.6 m/s.

Now if we put these value.
x + 800/60=21.6,
x + 800= 60 * 21.6,
x+800= 1296,
x= 1296 - 800.
x= 496.

Anyone please clarify this and explain with the correct answer.

Saikat said:   4 years ago
=> x+800/60 = 78 * 5/18,
=> x+800/60 = 65/3,
=> x+800 = 65 * 60/3,
=> x+800 = 1300,
=> x = 1300-800,
=> x = 500.
(1)

Adnan said:   5 years ago
To understand why we use 5/18 so i clarify that to convert km into m we multiply with 1000 and from hours to second we divided by 60*60.

Hence we get 5/18.
Suppose to change 1 km /hr into metre /sec.
1 * 1000/60 * 60 = 5/18.
(2)

ABDUL WAHAB SHAH said:   6 years ago
Last step:

3(800 + x) = 3900.
2400 + 3x = 3900.

3x = 3900 - 2400.
3x = 1500.

x = 1500/3.
x = 500.
(5)


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