Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 16)
16.
A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
2.5 min
3 min
3.2 min
3.5 min
Answer: Option
Explanation:

Total distance covered
= ( 7 + 1 ( miles
2 4
= 15 miles.
4

Therefore Time taken
= ( 15 ( hrs
4 x 75
= 1 hrs
20
= ( 1 x 60 ( min.
20
= 3 min.

Discussion:
129 comments Page 9 of 13.

Nivin said:   9 years ago
I agree with you @Sanjay Singh.

Abi said:   9 years ago
Why finally it convert into hours? Please explain.

Raju Ahmed said:   9 years ago
Total distance covered = 7/2(tunnel) + 1/4(length of train) + 1/4(length of train since the rear part is to be considered emerging) = 4 miles.

So total time taken = (4 miles/75mph ) * 60 mins.
= 3.2 mins.

So the answer is [C].

Appa rao said:   9 years ago
The answer should be option C.

Total distance covered = 7/2(tunnel) + 1/4(length of train) + 1/4(length of train since the rear part is to be considered emerging) = 4 miles.

So total time taken = (4 miles/75mph ) * 60 mins.
= 3.2 mins.

So the answer is option C.

Ajinath khedkar said:   9 years ago
Yes, Option C is the correct answer.

Sathish said:   9 years ago
Why this problem isn't convert the miles to meters or K.meters?

Priya said:   9 years ago
Please explain how come 60?

Priya said:   8 years ago
Can anyone explain 7/2+1/4=15/4 clearly?

Varinder said:   8 years ago
The total distance should be 7/2(tunnel)+1/4(while front entering in the tunnel)+1/4(while the rear is out of the tunnel) = 4 miles.

Prudhvi (palakol) said:   8 years ago
Simple 3.5 + 0.25 = 3.75,
3.75/75 = 0.05,
0.05 * 60 = 3.


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