Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 16)
16.
A train travelling at a speed of 75 mph enters a tunnel 3
miles long. The train is
mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?


Answer: Option
Explanation:
Total distance covered |
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= 3 min. |
Discussion:
129 comments Page 8 of 13.
Poonam goyal said:
9 years ago
Why you not change the miles into a meter?
Vishu said:
10 years ago
Time = Distance/Speed.
Time = (15/4)/75.
So how will it come like this 15/4*75?
Time = (15/4)/75.
So how will it come like this 15/4*75?
Anurag said:
10 years ago
@Geemee.
It already mentioned m=mile.
It already mentioned m=mile.
Geemee said:
10 years ago
How can we known that m=mile it can be meter?
Shubhendu said:
10 years ago
Question itself says, time from front of train enters to rear emerges.
So distance traveled should be 7/2 + 1/4 + 1/4 = 4.
So distance traveled should be 7/2 + 1/4 + 1/4 = 4.
Anjali said:
10 years ago
How did you know that the time found was in terms of hours?
Sudarsan said:
1 decade ago
Can any body explain, in the particular question my doubt is length is miles per hour and also unit of speed is also given in miles. Whether the length-speed or length-time is to be same unit of measurement to calculate the third?
I was thinking length-time-speed should be either Kilometer-hour-Kph or meter-seconds-meter per second.
I was thinking length-time-speed should be either Kilometer-hour-Kph or meter-seconds-meter per second.
Nitish Vajpayee said:
1 decade ago
Speed is given in meter/hr.
How come its taken with distance in miles and calculated (15/4)/75? How that possible different units?
How come its taken with distance in miles and calculated (15/4)/75? How that possible different units?
Neha said:
1 decade ago
Why we not convert 75 kmph to m/sec?
Suresh said:
1 decade ago
Ya friends let me explain it in detail, hope this will help you,
Given the speed of train = 75 mph which means (miles per hr). Because logically speaking there will be no train moving only 75 meters per one hour.
Tunnel length = 3 1/2.
= (3*2+1)/2 = 7/2 miles.
Train length = 1/4 mile.
So now as every thing is given in miles there is no need of any conversion. Now let us go to the problem.
For a train of length 'l' to cross a stationary object of length 'b' the time taken is equal to the time taken to cover (l+b) miles;
= 7/2+1/4.
Taking lcm as 4.
= ( (7*2) +1) /4.
=15/4.
Now the main confusion is to add another 1/4 distance or not. Here is the solution. It is not needed because.
At the start of train we are considering at entrance of the tunnel, so train length is not to be considered at starting end. But at the rear end of the tunnel it was said that trains rare end is to be passed, so rain length is to be added only once.
Now Speed = Distance/Time,
So, Time = Distance/Speed,
Now from above calculation.
Distance = 15/4 miles,
Speed = 75 miles per hour = 15/4 miles.
Time=-----------------75 miles/hr.
T = (15/ (75*4) ) hr.
T = 1/20 hrs.
T = 1/20*60 mins.
T = 3 minutes.
So the answer is 3 minutes.
Given the speed of train = 75 mph which means (miles per hr). Because logically speaking there will be no train moving only 75 meters per one hour.
Tunnel length = 3 1/2.
= (3*2+1)/2 = 7/2 miles.
Train length = 1/4 mile.
So now as every thing is given in miles there is no need of any conversion. Now let us go to the problem.
For a train of length 'l' to cross a stationary object of length 'b' the time taken is equal to the time taken to cover (l+b) miles;
= 7/2+1/4.
Taking lcm as 4.
= ( (7*2) +1) /4.
=15/4.
Now the main confusion is to add another 1/4 distance or not. Here is the solution. It is not needed because.
At the start of train we are considering at entrance of the tunnel, so train length is not to be considered at starting end. But at the rear end of the tunnel it was said that trains rare end is to be passed, so rain length is to be added only once.
Now Speed = Distance/Time,
So, Time = Distance/Speed,
Now from above calculation.
Distance = 15/4 miles,
Speed = 75 miles per hour = 15/4 miles.
Time=-----------------75 miles/hr.
T = (15/ (75*4) ) hr.
T = 1/20 hrs.
T = 1/20*60 mins.
T = 3 minutes.
So the answer is 3 minutes.
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