Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 16)
16.
A train travelling at a speed of 75 mph enters a tunnel 3
miles long. The train is 
mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
miles long. The train is mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?Answer: Option
Explanation:
| Total distance covered |
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 Time taken |
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| = 3 min. |
Discussion:
129 comments Page 12 of 13.
Gourab said:
1 decade ago
Yes aditya, you are absolutely rite, the answer should be 3. 2 min.
Aditya shukla said:
1 decade ago
Because train to pass through the tunnel from the moment the front enters to the moment the rear emerges. So we should add double the length of train then answer should be 3.2 min.
Uday said:
1 decade ago
In this problem we need time only that's why we are changing time only into minutes.
Chaithanyadeepthi said:
1 decade ago
7/2= 3*2+1/2;
But i have one doubt
Why don't we convert miles into meters can anyone explain this?
But i have one doubt
Why don't we convert miles into meters can anyone explain this?
Swetha said:
1 decade ago
I didn't understand? can any one explain ?
Swetha said:
1 decade ago
Why don't we convert miles into meter in this problem? I'm very confused. Can anyone explain the solution clearly? please.
Santhosh said:
1 decade ago
I did not get any clarity, I'm fluctuating between Gaurav and Manni.
Can any one explain?
Can any one explain?
Manni said:
1 decade ago
It will be 3mins.
Because total distance is 7/2 (tunnel) +1/4 (train).
When train starts entering tunnel there is nothing inside so why take 2 times.
Because total distance is 7/2 (tunnel) +1/4 (train).
When train starts entering tunnel there is nothing inside so why take 2 times.
Anitha said:
1 decade ago
Yes Gaurav I agree with you..
Total distance covered = 7/2(tunnel)+1/4(length of train)+1/4(length of train since the rear part is to be considered emerging)= 4 miles
So total time taken = (4 miles / 75mph ) * 60 mins
= 3.2 mins
So the answer is [C]
Total distance covered = 7/2(tunnel)+1/4(length of train)+1/4(length of train since the rear part is to be considered emerging)= 4 miles
So total time taken = (4 miles / 75mph ) * 60 mins
= 3.2 mins
So the answer is [C]
Gaurav said:
1 decade ago
I think the total distance = 7/2 + 1/4 + 1/4 = 4 miles as the summation of length of the tunnel, length of train when it enters and length of train when it emerges out should be taken.
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