Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 16)
16.
A train travelling at a speed of 75 mph enters a tunnel 3
miles long. The train is 
mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
miles long. The train is mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?Answer: Option
Explanation:
| Total distance covered |
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 Time taken |
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| = 3 min. |
Discussion:
129 comments Page 10 of 13.
Manju Gangadhar said:
7 years ago
75mph.
Where mph is miles per hour. Then only the answer is correct. If it is meters per hour then the given answer is wrong.
Where mph is miles per hour. Then only the answer is correct. If it is meters per hour then the given answer is wrong.
Nidhi kumari said:
7 years ago
The total distance should be,
(7/2 +2(1/4)) = 4miles,
So the required time will be 3.2 second.
(7/2 +2(1/4)) = 4miles,
So the required time will be 3.2 second.
Shalinwilson said:
7 years ago
3.75 miles.
3.75/75=.05,
.05 * 60 = 30min,
miles = meters.
3.75/75=.05,
.05 * 60 = 30min,
miles = meters.
Abhi said:
7 years ago
Here, it is asked for the time the front enters the rare emerges. So we will have to Add 1/4 more to the length of the Train Right.
Himaja said:
7 years ago
Can anyone explain about 7/2 how did we get it?
Phaneendra said:
7 years ago
I think here 75 is kmph not mph.
Praveen said:
7 years ago
So, if I change the speed to 90mph, then according to the way this is solved, the time would increase. Now that does not sound right to me. Can anyone explain this, please ?
Kumar tamang said:
7 years ago
How come 15/4 could you explain?
Naresh said:
7 years ago
Total distance covered.
= 7/2 + 1/4.
=15/4 miles.
Can anyone explain me, how to convert it?
= 7/2 + 1/4.
=15/4 miles.
Can anyone explain me, how to convert it?
Siddhant said:
7 years ago
@All.
Assume that there's a platform of length 7/2 miles and train of length 1/4 miles.
So now we just have to calculate the time taken by train to pass the platform.
Hence total distance = 15/4 miles.
No need to add 1/4 twice.
Hope you will understand.
Assume that there's a platform of length 7/2 miles and train of length 1/4 miles.
So now we just have to calculate the time taken by train to pass the platform.
Hence total distance = 15/4 miles.
No need to add 1/4 twice.
Hope you will understand.
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