Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
1 : 3
3 : 2
3 : 4
None of these
Answer: Option
Explanation:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

27x + 17y = 23
x+ y

27x + 17y = 23x + 23y

4x = 6y

x = 3 .
y 2

Discussion:
234 comments Page 17 of 24.

Mrk said:   8 years ago
Yeah, I got it (x+y) say relative speed.

Gowtham said:   8 years ago
Its very shortcut and its very simple.

27 17
2 3
6 4
The ans is 3:2 (or) 6:4.

Anil Bhadani said:   8 years ago
Its very shortcut and its very simple.

27-23 = 4
23-17 = 6
so,4:6 = 2:3 or 3:2 also.

Hima said:   8 years ago
Ratio of their speed = total distance travelled/total time taken= total speed.

(27x+17 y)/23 = (x+y),
27x+17y = 23x+23y,
4x = 6y,
x/y = 6/4,
3:2.

RAHUL tulskar said:   8 years ago
Look at this simplest ans.

Take both crossing time as an x y.
27as x 17 as y.
Then,
27x+17y/x+y=23.
27x+17y=23x+23y.
27x-23x=17y-23y.
4x =6y.
Or
XY=4/6or 2/3 get it.

Anuj said:   8 years ago
23-27:23-17.

4:6
2:3

Ashfaq said:   8 years ago
Distance /time = speed.

but here in solution
distance /time = time (i.e 23 seconds )

How it is possible?

UdoNe said:   8 years ago
27x+17y=DISTANCE.
x+y=SPEED,
23=TIME.

Latz said:   8 years ago
What if both trains will be in the same direction?

Angel said:   8 years ago
@Latz.

If both trains will be in the same direction then the equation becomes:
(27x+17y)/(x-y).


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