Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 4)
4.
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer: Option
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
 |
27x + 17y | = 23 |
| x+ y |
27x + 17y = 23x + 23y
4x = 6y
| |
x | = | 3 | . |
| y | 2 |
Discussion:
236 comments Page 24 of 24.
SAURABH PANDEY said:
9 months ago
Very well done. Thanks.
(6)
Thavapriya A said:
7 months ago
How to solve the following step?
27x+17y =23x+23y.
Could anyone tell me please?
27x+17y =23x+23y.
Could anyone tell me please?
(21)
Dripta Majumdar said:
6 months ago
Why is the length of the platform not taken into consideration? Anyone, please explain to me.
(9)
Anome said:
2 months ago
Very useful. Thanks all.
(7)
ARUN said:
1 month ago
I do not understand this. Please explain to me.
(3)
Student said:
1 month ago
A train takes 27 sec to reach man and 23 sec to cross train B, so the difference is 4 sec
B train takes 17 sec to reach the man and 23 sec to cross train A, so the difference is 6 sec.
Speed is inversely proportional to time, so the ratio of speed is 6:4.
So 3:2 is the answer.
B train takes 17 sec to reach the man and 23 sec to cross train A, so the difference is 6 sec.
Speed is inversely proportional to time, so the ratio of speed is 6:4.
So 3:2 is the answer.
(19)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers