Aptitude - Problems on Trains - Discussion

Guys, there is an easy way to understand this question.

Let us consider the SPEED of Train'A' and Train'B' as X and Y.

Trains moving in opposite direction which crosses a man standing on the platform signifies the TIME of trains taken to cross the man which are 27s and 17s respectively, not the time taken by trains to cross each other(given separately in the question).

Therefore,

DISTANCE of the trains taken to cross the man = SPEED * TIME.
D (TRAIN A)= X * 27.
D (TRAIN B)= Y * 17.

So, now we know that DISTANCE(LENGTH)covered by the trains and its SPEED(mentioned above).

From this, it is understood that its time to find out the TIME take by the trains.
But the time has already given;

TIME = DISTANCE/SPEED.

23 = 27x + 17y /x + y.
Cross multiply 23 (x + y) = 27x + 17y.

Bring all like terms on same sides; So,

23x + 23y = 27x + 17y.
23x - 27x = 17y - 23y.
- 4x = - 6y.

Since both the sides have a negative sign, it will automatically get deleted)ie, 4x = 6y .

Now its time to form the answer in ratio form.
Ratio forms when one digit is divided by the other digit, always remember NUMERATOR should be greater than DENOMINATOR.

4x = 6y .
(Bring all like terms on same sides).

Then, x/y = 6/4.
= 3/2 ie, 3 : 2.

Answer = 3 : 2.

An alternative answer:

27 - 23 = 4.
27 - 17 = 6.

Take the square root of both 6 and 4
=> 3:2.

In very simple method.

27 17

23

6 : 4
...................
3:2
..................

By using mixed alligation method.

The speeds of trains should be added because they are moving in opposite direction.

-------------> man < ----------------.

The speeds of both trains contributing to finish it in 23 seconds.

I couldn't get this part:

27x + 17y/x + y = 23.

As both trains are moving in opposite directions the equation must be:

27x + 17y/x - y = 23.

That is speeds must get subtracted why add both of them?

Hi @Gokulakisan sorry to say 27+23 = 50 not for 60.

You can use this simple method:

Time to cross men = tm.

Time to cross each other = te.

So 27(tm)+23(te) = 60.

17(tm)+23(te) = 40.

Then 60/40 = 3/2.

Therefore ratio is 3:2.

There is a simple method to solve this problem.

##Cross method##:

27 17
\ /
\ /
23
/ \
/ \
6 4

i.e, 27-23 = 4.

23-17 = 6.

6:4 so it is 3:2.

It is simplest form. I'm happy.

Two train of length a meter and b meter are moving in opposite direction at you m/s and we m/s then time taken by the faster train to cross the slower train = a+b/u+v.

Or in same direction = a+b/u-v.

In above problem train are in opposite direction.

So a = 27x & b = 17y (x = speed of fastest train y = speed of slow train).

= 27x+17y/x+y = 23.

4x = 6y.

x:y = 3:2.