Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 13)
13.
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
30 km/hr
45 km/hr
60 km/hr
75 km/hr
Answer: Option
Explanation:

Let the speed of the slower train be x m/sec.

Then, speed of the faster train = 2x m/sec.

Relative speed = (x + 2x) m/sec = 3x m/sec.

(100 + 100) = 3x
8

24x = 200

x = 25 .
3

So, speed of the faster train = 50 m/sec
3

   = 50 x 18 km/hr
3 5

   = 60 km/hr.

Discussion:
75 comments Page 7 of 8.

Priyesh Jain said:   1 decade ago
"D = ST".

Total distance = 100+100 = 200 m.

Relative speed = s+2s = 3s.

T= 8 sec.

Putting these values.

200 = 3s*8.

S = 200/8*3.

S = 25/3 m/s.

Now be need to calculate speed in terms of km/h.

25/3*18/5 = 30 km/h.

Speed of slower train now speed of faster train is 60 km/h that is just double.

Sudha said:   1 decade ago
I did not understand how you got 50/3? Please I need a clear explanation.

Studybeforexam said:   1 decade ago
25/3 + 25/3 = 50/3 i.e. 3 being a common denominator.

Mounika said:   1 decade ago
What 50/3 I didn't understand this step?

Swetha said:   1 decade ago
Hi @Raja,

5/18 is to convert KM to Meters.

18/5 is to convert Meters to KM.

As, in question it is given in Meters but answer is in meters so have to convert Meters to KM. So we are using.

Rajaprabu said:   1 decade ago
What is 18/5 and 5/18 ? why we are using please explain?

Khumalo said:   1 decade ago
Where is 3 coming from?

Charmi said:   1 decade ago
How did you reversed the 18/5 and multiplied with 50/3?

Divya said:   1 decade ago
Here there is no need of finding relative speed right? then why we find relative speed?

Thenmolzhi said:   1 decade ago
Relative speed = (x+y);
x = x;

y = Twice faster than 'x', So 2x;
y = 2x;

Relative speed = (x+2x) = 3x.


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