Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 13)
13.
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
30 km/hr
45 km/hr
60 km/hr
75 km/hr
Answer: Option
Explanation:

Let the speed of the slower train be x m/sec.

Then, speed of the faster train = 2x m/sec.

Relative speed = (x + 2x) m/sec = 3x m/sec.

(100 + 100) = 3x
8

24x = 200

x = 25 .
3

So, speed of the faster train = 50 m/sec
3

   = 50 x 18 km/hr
3 5

   = 60 km/hr.

Discussion:
74 comments Page 4 of 8.

Reeha said:   7 years ago
@Eudis.

It's the basic conversion principle, From km/hr to m/s we can use 5/18 and the reciprocal for vice versa.

Vaasudevarao said:   1 decade ago
Speed= d/t (100+100)=200*18/5=90km/h two train speed x+2x =3x 3x=90; x=90/3 x=30 so faster train speed is 2x =60

Jyoti said:   1 decade ago
Dear ravi this is speed of first train +speed of second train=relative speed of both trains moving opposite.

Thenmolzhi said:   1 decade ago
Relative speed = (x+y);
x = x;

y = Twice faster than 'x', So 2x;
y = 2x;

Relative speed = (x+2x) = 3x.

Navin said:   9 years ago
x = 25/3

So, speed of the faster train = 50/3 m/sec.

I can't understand these steps please help me.

Garvit said:   8 years ago
Why wasn't the speed of one train 1 considered x and other considered y? Why we're both taken as x?

Ganesh said:   7 years ago
Consider one train x speed and another one is x one twice speed to the other train then x+2x-3x.

Qweg said:   9 years ago
In this, we are not considering the distance that is between them? Should it be considered too?

Abhinav said:   1 decade ago
When the train is Opposite direction, than the relative speed is add to both (100+100)= 200

Seema said:   1 decade ago
If these two trains are moving in opposite direction then how can we add their distance.


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