Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 13)
13.
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
Answer: Option
Explanation:
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
|
(100 + 100) | = 3x |
| 8 |
24x = 200
x = |
25 | . |
| 3 |
| So, speed of the faster train = | 50 | m/sec |
| 3 |
| = | ![]() |
50 | x | 18 | km/hr |
| 3 | 5 |
= 60 km/hr.
Discussion:
74 comments Page 2 of 8.
Sarang said:
8 years ago
Distance =speed *time,
100+100=speed*8.
200=speed *8,
Speed=200/8,
Speed =25m/s,
Converting m/s into km/h.
25*18/5=90km/h,
As we want twice speed so first find single speed.
1+2 one is the speed of first train and 2 twice a second so combing we get 3 now,
Speed =90/3=30.
Now twice speed is 60km/h.
100+100=speed*8.
200=speed *8,
Speed=200/8,
Speed =25m/s,
Converting m/s into km/h.
25*18/5=90km/h,
As we want twice speed so first find single speed.
1+2 one is the speed of first train and 2 twice a second so combing we get 3 now,
Speed =90/3=30.
Now twice speed is 60km/h.
(1)
Mancy said:
1 decade ago
@Mounika.
We supposed the speed of the first train = x.
Nd speed of the faster train which is moving twice as fast the other = 2x (as we have given).
Now, given length of each train = 100m,
Time = 8sec,
Substitute these value in formula.
Time = (distance/speed).
8sec = (100+100/x+2x).
"Here we are adding the values b'coz the trains are in opposite direction with each other, which you can easily understand by reading the formula column. ".
8 = 200m/3x.
By cross multiplication.
24x sec = 200m.
x = 200/24.
x = 25/3 m/sec.
When we convert it into km/hr it becomes.
x = 30km/hr but.
Acc. To question they are asking for faster train which is 2x.
So by putting the value of x in 2x we'll get the correct answer.
2(30km/hr).
Answer = 60 km/hr.
We supposed the speed of the first train = x.
Nd speed of the faster train which is moving twice as fast the other = 2x (as we have given).
Now, given length of each train = 100m,
Time = 8sec,
Substitute these value in formula.
Time = (distance/speed).
8sec = (100+100/x+2x).
"Here we are adding the values b'coz the trains are in opposite direction with each other, which you can easily understand by reading the formula column. ".
8 = 200m/3x.
By cross multiplication.
24x sec = 200m.
x = 200/24.
x = 25/3 m/sec.
When we convert it into km/hr it becomes.
x = 30km/hr but.
Acc. To question they are asking for faster train which is 2x.
So by putting the value of x in 2x we'll get the correct answer.
2(30km/hr).
Answer = 60 km/hr.
(1)
Fabarah Israr said:
5 years ago
Can someone please tell me, we are already multiplying 2 with x then why we are again multiplying with 2 with 25/6? Please explain me.
(1)
Praveen Sharma said:
1 decade ago
Here (100+100)/8 = 3x.
200/8 = 3x.
25 = 3x.
So x = 25/3 m/s it is speed of slow train.
We want speed of fast train, it is 2x where x = 25/2 m/s.
So speed of fast train = 2*25/3 m/s.
So 50/3 m/s.
And we convert in km/s using 18/5.
So (50*18)/(3*5) = 900/15 = 60 km/h.
200/8 = 3x.
25 = 3x.
So x = 25/3 m/s it is speed of slow train.
We want speed of fast train, it is 2x where x = 25/2 m/s.
So speed of fast train = 2*25/3 m/s.
So 50/3 m/s.
And we convert in km/s using 18/5.
So (50*18)/(3*5) = 900/15 = 60 km/h.
(1)
Roshan Kumar said:
5 years ago
Answer will be 30km/hr.
Because the simplification of 200/24 = 25/6.
But in the answer it's given as 25/3 that's why the answer is changed to 60 km/hr.
Because the simplification of 200/24 = 25/6.
But in the answer it's given as 25/3 that's why the answer is changed to 60 km/hr.
(1)
Praveen Sharma said:
1 decade ago
How come 3?
Answer - If speed of slow train is x km/h.
In question the speed of fast train is twice to slow train.
So speed of fast train = 2*(Speed of slow train).
So speed of fast train = 2*(x) = 2x.
If trains are moving in opposite direction then we ADD the Speed. And trains are in same direction then we sub speed.
Here train in same direction so we add the speed of both train.
So x + 2x = 3x.
Answer - If speed of slow train is x km/h.
In question the speed of fast train is twice to slow train.
So speed of fast train = 2*(Speed of slow train).
So speed of fast train = 2*(x) = 2x.
If trains are moving in opposite direction then we ADD the Speed. And trains are in same direction then we sub speed.
Here train in same direction so we add the speed of both train.
So x + 2x = 3x.
Srinu said:
1 decade ago
What is formula distance?
Sam said:
1 decade ago
@Aditiyabala.
Super explanation, Thank you.
Super explanation, Thank you.
Jai said:
10 years ago
If 1st train accelerated by 0.3 and 2nd 0.2 then how to solve it?
Shiva said:
1 decade ago
Why you are all talking always 5/18 to convert kmph into m/sec, I can't understand that logic, please explain reason behind that. Thanks in advance.
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