Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 13)
13.
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
Answer: Option
Explanation:
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
![]() |
(100 + 100) | = 3x |
8 |
24x = 200
![]() |
25 | . |
3 |
So, speed of the faster train = | 50 | m/sec |
3 |
= | ![]() |
50 | x | 18 | ![]() |
3 | 5 |
= 60 km/hr.
Discussion:
74 comments Page 2 of 8.
Fabarah Israr said:
4 years ago
Can someone please tell me, we are already multiplying 2 with x then why we are again multiplying with 2 with 25/6? Please explain me.
(1)
Sarang said:
7 years ago
Distance =speed *time,
100+100=speed*8.
200=speed *8,
Speed=200/8,
Speed =25m/s,
Converting m/s into km/h.
25*18/5=90km/h,
As we want twice speed so first find single speed.
1+2 one is the speed of first train and 2 twice a second so combing we get 3 now,
Speed =90/3=30.
Now twice speed is 60km/h.
100+100=speed*8.
200=speed *8,
Speed=200/8,
Speed =25m/s,
Converting m/s into km/h.
25*18/5=90km/h,
As we want twice speed so first find single speed.
1+2 one is the speed of first train and 2 twice a second so combing we get 3 now,
Speed =90/3=30.
Now twice speed is 60km/h.
(1)
Praveen Sharma said:
10 years ago
Here (100+100)/8 = 3x.
200/8 = 3x.
25 = 3x.
So x = 25/3 m/s it is speed of slow train.
We want speed of fast train, it is 2x where x = 25/2 m/s.
So speed of fast train = 2*25/3 m/s.
So 50/3 m/s.
And we convert in km/s using 18/5.
So (50*18)/(3*5) = 900/15 = 60 km/h.
200/8 = 3x.
25 = 3x.
So x = 25/3 m/s it is speed of slow train.
We want speed of fast train, it is 2x where x = 25/2 m/s.
So speed of fast train = 2*25/3 m/s.
So 50/3 m/s.
And we convert in km/s using 18/5.
So (50*18)/(3*5) = 900/15 = 60 km/h.
(1)
Sudha said:
1 decade ago
When you divide 200/24, you won't get 25/3? So I request you to explain me properly.
(1)
Mancy said:
1 decade ago
@Mounika.
We supposed the speed of the first train = x.
Nd speed of the faster train which is moving twice as fast the other = 2x (as we have given).
Now, given length of each train = 100m,
Time = 8sec,
Substitute these value in formula.
Time = (distance/speed).
8sec = (100+100/x+2x).
"Here we are adding the values b'coz the trains are in opposite direction with each other, which you can easily understand by reading the formula column. ".
8 = 200m/3x.
By cross multiplication.
24x sec = 200m.
x = 200/24.
x = 25/3 m/sec.
When we convert it into km/hr it becomes.
x = 30km/hr but.
Acc. To question they are asking for faster train which is 2x.
So by putting the value of x in 2x we'll get the correct answer.
2(30km/hr).
Answer = 60 km/hr.
We supposed the speed of the first train = x.
Nd speed of the faster train which is moving twice as fast the other = 2x (as we have given).
Now, given length of each train = 100m,
Time = 8sec,
Substitute these value in formula.
Time = (distance/speed).
8sec = (100+100/x+2x).
"Here we are adding the values b'coz the trains are in opposite direction with each other, which you can easily understand by reading the formula column. ".
8 = 200m/3x.
By cross multiplication.
24x sec = 200m.
x = 200/24.
x = 25/3 m/sec.
When we convert it into km/hr it becomes.
x = 30km/hr but.
Acc. To question they are asking for faster train which is 2x.
So by putting the value of x in 2x we'll get the correct answer.
2(30km/hr).
Answer = 60 km/hr.
(1)
R.Rakesh KUmar said:
8 years ago
@Navin.
In question they have mentioned to calculate the speed of faster train i.e to calculate 2X
X=25/3 is the speed of the slower train and ( " If one is moving twice as fast the other" given in question).
2 * X = 2 * 25/3 => 50/3.
In question they have mentioned to calculate the speed of faster train i.e to calculate 2X
X=25/3 is the speed of the slower train and ( " If one is moving twice as fast the other" given in question).
2 * X = 2 * 25/3 => 50/3.
Sonam said:
9 years ago
@Adityabala.
Nice explanation. Thanks.
Nice explanation. Thanks.
Navin said:
9 years ago
x = 25/3
So, speed of the faster train = 50/3 m/sec.
I can't understand these steps please help me.
So, speed of the faster train = 50/3 m/sec.
I can't understand these steps please help me.
Qweg said:
9 years ago
In this, we are not considering the distance that is between them? Should it be considered too?
Vijay arun said:
9 years ago
@Ikram.
Nice explanation.
Nice explanation.
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