Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 11)
11.
A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
230 m
240 m
260 m
320 m
None of these
Answer: Option
Explanation:

Relative speed = (120 + 80) km/hr

   = 200 x 5 m/sec
18

   = 500 m/sec.
9

Let the length of the other train be x metres.

Then, x + 270 = 500
9 9

x + 270 = 500

x = 230.

Discussion:
66 comments Page 7 of 7.

Pankaj kumar marskole said:   1 decade ago
Time taken crossed the train=length of the both train/length of the speed.

Let length of the 2nd train is x.

9= (270+x)/(100/3+200/9).

X=230.

Arulmozhi said:   1 decade ago
Hai friends,

Having any other shortcut method to this problem?

Randhir said:   1 decade ago
If two trains of length a metres and b metres are moving in opposite directions at u m/s and v m/s, then:

The time taken by the trains to cross each other =(a+b)/(u+v)

Then time is 9 sec, a=270 metres, b=x metres, u=120 kmph,
v=80 kmph

Therefore 9=(270+x)/(120+80)*5/18
we multiply (120+80) by 5/18 because converting kmph into m/sec
5/18*200*9=270+x
x=230

Pavan said:   1 decade ago
Why you add X and 270 ?

Ajantha said:   2 decades ago
Hi meenu,
Total speed(Relative speed) of two trains=120+80=200km/hr
we derived this from km/hr to meter/sec
=200*5/18 (bcas1000/3600=5/18)
=1000/18
=500/9

Meenu said:   2 decades ago
In this solution how you are multiplying 5/18 with 200.

I can't understand that wll you please explain me that.


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