Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 11)
11.
A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
Answer: Option
Explanation:
Relative speed = (120 + 80) km/hr
| = |  |
200 x | 5 |  m/sec |
| 18 |
| = | |
500 | m/sec. |
| 9 |
Let the length of the other train be x metres.
| Then, | x + 270 | = | 500 |
| 9 | 9 |
x + 270 = 500
x = 230.
Discussion:
66 comments Page 4 of 7.
Gaurav said:
8 years ago
Relative speed is 120 +80 =200.
Now l =s*t =200*5/18*9=500,
Now, the total dist minus 500-270=230m.
Now l =s*t =200*5/18*9=500,
Now, the total dist minus 500-270=230m.
Moni said:
1 decade ago
Relative speed should be minus from each train speed because the direction is opposite, isn't it so?
Jagadheesh said:
1 decade ago
How to find that this problem is need to convert km/hr to m/s or m/s to km/hr. Please explain?
Krishna said:
1 decade ago
The speed & time of the other so we can directly get the length of the other train.
Janani said:
1 decade ago
I want to know one thing usually where we use or apply this relative speed concept ?
Kd kannan said:
1 decade ago
To aswin:
100/3 and 120 (5/18).
Two values are equal.
It is another form of 33.3.
100/3 and 120 (5/18).
Two values are equal.
It is another form of 33.3.
Ronit said:
1 decade ago
Easy way.
270 + x
---------------- = 9.
33.33+22.22
x = 499.5 - 270.
x = 229.5.
270 + x
---------------- = 9.
33.33+22.22
x = 499.5 - 270.
x = 229.5.
Krishna said:
9 years ago
Thanks Indiabix, because of this discussion section I can understand that tricks.
Sarang said:
7 years ago
Distance =speed *time,
D=120+80km/h*9,
D=200*5/18*9,
D=1000/2,
D=500-270=230m.
D=120+80km/h*9,
D=200*5/18*9,
D=1000/2,
D=500-270=230m.
(1)
Maneesh said:
1 decade ago
Can anyone please tell me when to add or subtract the given relative speeds.
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