Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 11)
11.
A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
Answer: Option
Explanation:
Relative speed = (120 + 80) km/hr
= | ![]() |
200 x | 5 | ![]() |
18 |
= | ![]() |
500 | ![]() |
9 |
Let the length of the other train be x metres.
Then, | x + 270 | = | 500 |
9 | 9 |
x + 270 = 500
x = 230.
Discussion:
66 comments Page 2 of 7.
Nikita said:
9 years ago
Right. But in the question trains are running in opposite side.
So speed is subtracted ie 120-80 = 40.
Am I correct?
So speed is subtracted ie 120-80 = 40.
Am I correct?
(1)
Srujana said:
9 years ago
Why we writing denominator 9 for x+270?
(1)
Sarang said:
7 years ago
Distance =speed *time,
D=120+80km/h*9,
D=200*5/18*9,
D=1000/2,
D=500-270=230m.
D=120+80km/h*9,
D=200*5/18*9,
D=1000/2,
D=500-270=230m.
(1)
Onkar Babar said:
5 years ago
how we take x+270÷9? Please explain.
(1)
Rishikesh said:
2 months ago
Thanks everyone, for explaining it.
Karn sharma said:
1 decade ago
Trains are move in opposite direction. But out of speed n distance one quantity is subtract but in the solution of this question both are added. Please explain I can't understand.
Anurag said:
1 decade ago
D = S*T = 270+x = 500/9*9.
So x = 500-270 = 230.
So x = 500-270 = 230.
Swathi said:
10 years ago
Thanks alot. It is very helpful to me.
Arun said:
10 years ago
When we add the relative speed when substract please tell me?
Hannan said:
9 years ago
It's simple and just take it easy.
When two trains running on the same site then relative speed is add, running in opposite site then we subtract it.
When two trains running on the same site then relative speed is add, running in opposite site then we subtract it.
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