Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
481 comments Page 46 of 49.

Sonali said:   6 years ago
If only one of the speed is given then how will we consider that which one is to be subtracted or not?

Siddharth said:   6 years ago
We 1st Find the speed of train relative to man Vr.
Man and train moved in the same direction = (V-U).
V = Speed of the train.
U = Speed of man.
Vr = (V-U).

Pradeep said:   6 years ago
It's 50 m/s unit.

Sonu said:   6 years ago
x-5 = 45.
x = 45+5(because when 5 goes from the left side to right then it will be added into 45).

So,
x = 50 Answer.

PKP said:   6 years ago
Wrong solution.

Man also traveled a distance of 5*5/18*10=125/9 m in 10 sec. So this distance should be added to 125 m when calculating relative speed, so relative speed = (125+125/9)/10 = 125/9 m/s = 125/9 * 18/5 km/s = 50 km/hr.

So the speed of the train is 50+5 = 55 km/hr.

Alan. said:   6 years ago
How x-5 came?

Lakshmi said:   6 years ago
Relative speed subtracted by actual speed so we get X - 5.

Kavya said:   6 years ago
Why it is divided 125/10? Please explain.

Luci said:   6 years ago
We are finding the speed of the train.
So,
Speed = distance /time.
=> Speed = 125/10.

Azhr said:   5 years ago
(X-5) * 5/18 = 125/10.


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