Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = | ![]() |
125 | m/sec |
| 10 |
| = | ![]() |
25 | m/sec. |
| 2 |
| = | ![]() |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
487 comments Page 40 of 49.
Arun said:
7 years ago
How we say 45 km/hr is a relative speed?
Sayak Chakraborty said:
2 years ago
How 18/5 came after 25/2? Please answer.
(16)
Suja said:
9 months ago
How it 18รท5 will become? Please explain.
(16)
Parvez khan said:
1 decade ago
How was the relative speed calculated ?
Vignesh.Rv said:
9 years ago
Anyone tell me why its divided by 18/5?
Akshit mahajan said:
9 years ago
Could anyone tell. Why we had done x-5?
Subu D. said:
8 years ago
125 = speed /10.
Speed = 125/10= 25/2.
Speed = 125/10= 25/2.
Owona Julius said:
3 years ago
How - 5 came? Please explain this step.
(17)
Amit said:
2 decades ago
Hi friend's
Hey ravi nice explanation.
Hey ravi nice explanation.
Uma said:
1 decade ago
Manoj explanation s superb. Thank you.
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