Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
487 comments Page 40 of 49.

Arun said:   7 years ago
How we say 45 km/hr is a relative speed?

Sayak Chakraborty said:   2 years ago
How 18/5 came after 25/2? Please answer.
(16)

Suja said:   9 months ago
How it 18รท5 will become? Please explain.
(16)

Parvez khan said:   1 decade ago
How was the relative speed calculated ?

Vignesh.Rv said:   9 years ago
Anyone tell me why its divided by 18/5?

Akshit mahajan said:   9 years ago
Could anyone tell. Why we had done x-5?

Subu D. said:   8 years ago
125 = speed /10.

Speed = 125/10= 25/2.

Owona Julius said:   3 years ago
How - 5 came? Please explain this step.
(17)

Amit said:   2 decades ago
Hi friend's
Hey ravi nice explanation.

Uma said:   1 decade ago
Manoj explanation s superb. Thank you.


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