Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
475 comments Page 38 of 48.
Lavanya said:
7 years ago
Why do we to subtract 45-5? please clarify that.
Narendra said:
7 years ago
In same direction, T. S-M. S = 125/10 * 18/5 = 45.
M.S = 5KMph.
T.S - 5 = 45.
T.S = 50sec.
M.S = 5KMph.
T.S - 5 = 45.
T.S = 50sec.
Abuthahir said:
7 years ago
X-5 = 45.
Here x = 45+5,
Then x = 50.
Here x = 45+5,
Then x = 50.
Anjali said:
7 years ago
Thanks all for explaining the answer.
Vinod said:
7 years ago
Thanks all for explaining the answer.
Muhammad Zulafqar said:
7 years ago
The simplest answer is;
10sec/1000Meter =0.01.
Then multiply with 5KM i.e 0.01 * 5000meter = 50KM.
10sec/1000Meter =0.01.
Then multiply with 5KM i.e 0.01 * 5000meter = 50KM.
Nithish said:
7 years ago
Thanks all for the explanations.
Mozammel hossain said:
7 years ago
There have man speed but not train speed.
So we known that;
speed = distanc/time.
= 125/10,
= 25/2.
Now convert into km/h.
25/2 * 18/5.
= 45km/h.
Lets train speed is x km/h.
So, the relative speed is x-5 km/h.
x- 5 = 45,
X = 50km/h.
So we known that;
speed = distanc/time.
= 125/10,
= 25/2.
Now convert into km/h.
25/2 * 18/5.
= 45km/h.
Lets train speed is x km/h.
So, the relative speed is x-5 km/h.
x- 5 = 45,
X = 50km/h.
Kunal Pardeshi said:
6 years ago
Hi. please solve my query.
Since the man is also moving, why the distance travelled by train in 10 seconds is considered equivalent to the length of the train when in actuality the distance covered will be more than that as the man is not stationary. Please, somebody explain this clearly. I want to know the concept and logic behind this.
Since the man is also moving, why the distance travelled by train in 10 seconds is considered equivalent to the length of the train when in actuality the distance covered will be more than that as the man is not stationary. Please, somebody explain this clearly. I want to know the concept and logic behind this.
P. Sudha said:
6 years ago
How 18/5 possible? Please explain to me.
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