Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
475 comments Page 37 of 48.
Chinmay said:
8 years ago
Thank you @Rahul.
Vishal said:
8 years ago
@Rachit.
The answer should be in m/s according to it not in km/hr.
The answer should be in m/s according to it not in km/hr.
Sathish Chandran said:
8 years ago
May I know why we multiply the speed by 18/5?
Sivalaxman said:
8 years ago
They are two formulas for this,
1. X mts/sec = X*18/5 km/hr,
2. X km/hr = X*5/18mts/sec,
When you see the question the options are given in km/hr then we 1. Formula for this solution.
1. X mts/sec = X*18/5 km/hr,
2. X km/hr = X*5/18mts/sec,
When you see the question the options are given in km/hr then we 1. Formula for this solution.
Siva laxman said:
8 years ago
The relatie speed of the train = if opp direction = s1+s2.
Same direction s1~s2.
Same direction s1~s2.
Rony shaha said:
8 years ago
Speed*time=distance or pole's length,
How I can calculate length of train?
How I can calculate length of train?
Chandrasekar said:
8 years ago
Why using 18/5?
Please explain.
Please explain.
Bala said:
8 years ago
Why are you divided 125/10 at the 1st step? Please explain.
ASHWINI said:
8 years ago
Thank to all the given explanation.
Jeevitha said:
8 years ago
Here 18/5 used. Because to convert 125m to km/hr from km/hr to m/sec multiply by 5/18.
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