Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
475 comments Page 30 of 48.

Venkatesh said:   8 years ago
Thank you @Nagapriya.

Ganga said:   8 years ago
Why we subtract (x-5)?

Shailesh Hiremath said:   8 years ago
So, kilometre & minutes will be calculated as 1 km=1000 mtrs and 60 minutes =3600 seconds.

If you divide 3600/1000 = 5/18.

Sunil said:   8 years ago
Thank you all for the given explanations.

Basava g said:   8 years ago
First, we find total length to across moving man=125+((5*10^3)÷(3600))*10.

= 125+13.888.
= 138.88m.

The speed of train = total/time.
= 138/10,
= 13.88m/s.

This one convert into km/hrs.
= 13.88 * 3600,
= 50km/hrs.

Manjunath said:   8 years ago
Hi, anyone please explain to me why we should take 5/18?

Rachit said:   8 years ago
RELATIVE SPEED OF TRAIN WITH RESPECT TO MAN RUNNING= (x-5)km/hr.
TIME=DISTANCE/RELATIVE SPEED.
Therefore we know that- to convert km/hr to m/s we have to use,
(x-5) * 5/18)m/sec.

TIME=DISTANCE/RELATIVE SPEED
10=125/(x-5)*5/18.
10=TIME,125=DISTANCE,(x-5)*5/18=RELATIVE SPEED

CALCULATION-
10=125/(x-5)*5/18,
10=125*18/5x-25,
10=2250/5x-25,
10(5x-25)=2250,
50x-250=2250,
50x=2500,
x=50km/hr.

Ananya said:   8 years ago
How can the answer be 50 that's the point x-5 would be 40 kmph?

Then how can b be the answer?

Gaurav said:   8 years ago
Hey someone tell me, please. Why are you using 18/5 then 5/18?

Because the unit is m/s = 5/18 and you are using 18/5 in this problem.

Saikat Dey said:   8 years ago
Thanks to all for such nice explanations.


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