Aptitude - Problems on Trains - Discussion

125m/10s*18/5=45.

The man running in opposite direction at a speed of 5 km so 45+5=50.

I have a doubt on question. Whose speed is 5km/hr? either the man's or train's? please explain.

Why use 60*60/1000(18/5) I do not understand that?

Please explain.

Why use 60*60/1000(18/5) I do not understand that?

@Jothi,

x-5 = 45.
We add 5 to both sides so that we stay with x.

x-5+5 = 45+5.
Therefore,

So x = 50.

Hi @Swati look here let me explain:
L = Speed*time.

And,
Speed = length/time.
Length = 25/2.
Time = 5/18.

And,
25/2/5/18 = 25/2*18/5.
9*5 = 45km/hr.
x-5 = 45.

45+5 = x.
x = 50km/hr.

Relative speed = x-5 (x is the speed of train).
(x-5)*5/18 = 125/10.
x-5 = 125*18/10*5.
x-5 = 125*9/25.
x-5 = 5*9.
x-5 = 45.
x = 50.

The only thing to remember is that when objects are moving in the same direction,then relative speed is equal to subtraction of their respective speeds and when the objects are moving in opposite direction,then relative speed is equal to addition of their respective speeds.

Therefore, here v1 = 5 km/h, v2=?, t=10sec => 10/3600 hr.,
Distance = 125 mt => 125/1000 kms.

Now we know, Speed=distance/time.
or we can say, Relative speed = distance/time.

Since here relative speed= v2-v1 (objects moving in same direction).
Therefore, v2-5=125/1000 whole divided by 10/3600.

or, v2-5=125/1000 * 3600/10, on solving we get,
v2-5= 45 => v2 = 45+5 => V2=50 Km/hr.

How the will be 50?
Speed = 25/2(m/s).

Converting(m/s)to(km/hr).
25/2*18/5 = 45.

@Hemavathy. Since man is moving in same direction with train the relative speed is s-5 so,

s-5 = 45.
s = 50 km/hr.


Suppose if man move in opposite direction of train then,

s+5 = 45.
s = 40 km/hr.