Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
476 comments Page 21 of 48.

Karthik said:   1 decade ago
125/10 = 25/2

25/2*18/5 = 450/10
45

friends,
i don't know how to solve this problems after this
so plz anyone help me out

Vijaya said:   1 decade ago
Hi amit and Sarah

Here x - 5 = 45
x= 45 + 5 (when minus (-) simble comes from right of = to left of = it will become +.

Priya said:   8 years ago
As both the man and train are moving in the same direction than why the relative is subtracted by 5 i.e, x-5 it should be x+5?

K.C.Yogannal said:   1 decade ago
@Vijayagopal.

As speed =length/time they have done 125/10. Where 125 is the length and 10 is the time. Hope you understood.

Gowthami said:   1 decade ago
Nice explanation from you frnds but ravi said that we had add that relative speed, I can't understand from his point of view.

Harish said:   1 decade ago
It is brain storming and conceptual question .Thank you for giving more explanation on this question.Thank you very much....!

Mohit kumar said:   1 decade ago
1 km = 1000 m/1 hr = 3600 sec = 5/18 but we want to convert just opposite.

So numerator and denominator will be interchange.

Deepak said:   1 decade ago
In first problem you mentioned that meters per sec is equal to 5/18 but then you are taking like 18/5 why so please tell me.

Nishant said:   8 years ago
But it should have been given that we have to find the relative velocity of the man. So, 45km/hr should be the right answer.

Iliyas said:   3 years ago
m/sec = [1/1000 km] / [1/3600 sec]
= [1/1000] *[3600/1],
= [3600/1000].
= [18/5]km/hr.
(28)


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