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Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
Problems on Trains
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
487 comments Page 18 of 49.
Jeevitha said:   9 years ago
Somebody asking that why x-5 here. Note that the man running in the same direction. So we have to subtract. If it is opp we have to add. Because man beats train spd. So man power should be subtracted. Then only we can get an exact speed of the train.
Jeevitha said:   9 years ago
Here 18/5 used. Because to convert 125m to km/hr from km/hr to m/sec multiply by 5/18.
ASHWINI said:   9 years ago
Thank to all the given explanation.
Bala said:   9 years ago
Why are you divided 125/10 at the 1st step? Please explain.
Chandrasekar said:   9 years ago
Why using 18/5?

Please explain.
Rony shaha said:   9 years ago
Speed*time=distance or pole's length,

How I can calculate length of train?
Siva laxman said:   9 years ago
The relatie speed of the train = if opp direction = s1+s2.
Same direction s1~s2.
Sivalaxman said:   9 years ago
They are two formulas for this,

1. X mts/sec = X*18/5 km/hr,
2. X km/hr = X*5/18mts/sec,

When you see the question the options are given in km/hr then we 1. Formula for this solution.
Vishal said:   9 years ago
@Rachit.

The answer should be in m/s according to it not in km/hr.
Sathish Chandran said:   9 years ago
May I know why we multiply the speed by 18/5?
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