Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
476 comments Page 17 of 48.
Srikanth Mirdati said:
1 decade ago
Could anyone please tell me how we get to 25/2 by dividing 125/10. I want to know how the division of 125/10 is done to get 25/2 an answer would be appreciated greatly.
Apoorva E said:
7 years ago
Whenever you convert speed from km/hr to m/sec you should multiply the speed by 5/18.
Vice versa when you convert m/sec to km/hr you should multiply the speed by 18/5.
Vice versa when you convert m/sec to km/hr you should multiply the speed by 18/5.
Fizza akhtar said:
1 year ago
Suppose we have to convert km/hour into m/s.
km/hour = 1000m/hour
i hour = 3600s
km/s = 1000m/3600s = 5/18.
Just reverse it, m/s into km/hour = 18/5, it's an easy way.
km/hour = 1000m/hour
i hour = 3600s
km/s = 1000m/3600s = 5/18.
Just reverse it, m/s into km/hour = 18/5, it's an easy way.
(11)
Preethi said:
1 decade ago
A train of length 110mtr travelling at a speed of 80km/hr. Find the time taken by that train to overtake a train having length 130mtr travelling at a speed of 62km/hr?
Amol said:
1 decade ago
Hi Friend's
Thanks for teaching it really works dude ,
1km=1000m and 1hr =36000 then 5/18 m/sec it's simple.
Thanks for that .........!
Thanks for teaching it really works dude ,
1km=1000m and 1hr =36000 then 5/18 m/sec it's simple.
Thanks for that .........!
Mustufa said:
8 years ago
As we find train speed pass near to man is 45 km/hr and man also running at speed of 5 km/hr so we add train speed with man speed so we get the exact speed of train.
Raja simhan said:
1 decade ago
Here the train is crossing a moving object rather than a stationary object like a pole. Then how it is possible to say its relative speed to man is (125/10) m/sec ?
Sagar said:
1 decade ago
Finally we need to find speed me train. But in problem train speed is compared with moving object i.e man. So (total speed of train-speed of man=relative speed).
Shashi said:
9 years ago
@Krishna.
The thought of shortcut methods comes when we are not able to understand the problem. My word is understanding a problem clearly is itself a shortcut.
The thought of shortcut methods comes when we are not able to understand the problem. My word is understanding a problem clearly is itself a shortcut.
Murugan S said:
1 year ago
HERE,
1hr = 3600sec then, 1sec = 1/3600hr
1km =1000m then, 1m = 1/1000km
So,
km/hr to m/s is : 1/1000km bigger divided by 1/3600hr.
So, they put 18/5.
1hr = 3600sec then, 1sec = 1/3600hr
1km =1000m then, 1m = 1/1000km
So,
km/hr to m/s is : 1/1000km bigger divided by 1/3600hr.
So, they put 18/5.
(21)
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