Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
Speed of the train relative to man = | ![]() |
125 | ![]() |
10 |
= | ![]() |
25 | ![]() |
2 |
= | ![]() |
25 | x | 18 | ![]() |
2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
478 comments Page 14 of 48.
Veni balamurugan said:
7 years ago
How come 25/2? Please explain.
Bouvthika R.M said:
7 years ago
Here please explain for what reason it becomes (X-5).
I can't understand.
I can't understand.
Suraj Kumar Swami said:
7 years ago
x-5 = 45 the result should be 40, then why it is 50?
Vikash gupta said:
7 years ago
Relative velocity is 125/10, how?
Bharat Gupta said:
7 years ago
Please explain the relative speed = (x - 5) km/hr.
Apoorva E said:
7 years ago
Whenever you convert speed from km/hr to m/sec you should multiply the speed by 5/18.
Vice versa when you convert m/sec to km/hr you should multiply the speed by 18/5.
Vice versa when you convert m/sec to km/hr you should multiply the speed by 18/5.
Sarang said:
7 years ago
Distance=speed * time.
In same direction speed is added,
125=speed*10,
125/10= speed,
12.5 *18/5,
45 relative speed of train,
5 + 45 = 50.
In same direction speed is added,
125=speed*10,
125/10= speed,
12.5 *18/5,
45 relative speed of train,
5 + 45 = 50.
Satya said:
7 years ago
Why is it divided by 18/5 and how it is? Please explain.
Shivam tomar said:
7 years ago
Speed of the train relative to man = 125/10 m/sec.
I am confused in this step, please clarify it.
I am confused in this step, please clarify it.
Koser said:
7 years ago
Why is it divided by 125/10?
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