Aptitude - Problems on Trains - Discussion

hai raghu, in the question man's speed is given in km/hr so we gonna convert train's speed to km/hr which is actually in m/s
1 m/s = 3600 km/1000 hr
125/10 m/s= (125/10)*(3600/1000)

Ramesh chandran.

CLEAR explanaTION. THANKS.

Hi Tahira,

You just cancel 125/10 using multiples of 5.

125/10=25/2=12.5.

NICE EXPLANATION ABHISHEK.

Hi Friend's
Thanks for teaching it really works dude ,
1km=1000m and 1hr =36000 then 5/18 m/sec it's simple.

Thanks for that .........!

Hi friend's
Hey ravi nice explanation.

@ all apply logic don't simply go for routine

speed of man is 5km/hr and in mt/sec is 1.39.
so total distance covered by main in 10 sec is 13.9 m
so total distance covered by train in 10 sec is 125+13.9=138.9
so total distance covered by train in 1 sec is 13.89m
and if we convert this in km/hr
i.e. 13.89*3600/1000= 50km/hr

Thanks Amit

Train moves with speed 125m/10 sec,.. So need to convert it as KM/ Hr ,..To convert 125m to KM we have to divide it with 1000 so it is 125/1000 and to convert 10 sec to hrs we have to divide it with 3600 so it is 10/3600.
Then it becomes (125/1000)Km/(10/3600)hr.
So we can change it to (125/1000)*(3600/10)..
It is (5/40)*(360) = (360*5)/40 = 180/4 = 45 Km/Hr.

.. Now we have got the speed in 1 Hour ie 45 Km..

As the man is travelling at 5 Km/Hr.. In that 1 Hr he already travelled 5 Km's.. So the train speed should be 45+5 Km's to cross that person in that 1 Hr.. Now answer is 50 Km/Hr.. I hope it is clear,... Take a paper a write exactly what i have given above,.. I am sure u guys will like it..

Can anyone find another way of solving this? Apart from relative speed?