Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
475 comments Page 11 of 48.
Raghu said:
1 decade ago
How it is 3600/1000. It will come as 1000/3600 only. Please explain.
Tahira said:
1 decade ago
Hai fnds.
Howz the 12.5 is converted into 25.
Please explain.
Howz the 12.5 is converted into 25.
Please explain.
Saranya said:
1 decade ago
hai raghu, in the question man's speed is given in km/hr so we gonna convert train's speed to km/hr which is actually in m/s
1 m/s = 3600 km/1000 hr
125/10 m/s= (125/10)*(3600/1000)
1 m/s = 3600 km/1000 hr
125/10 m/s= (125/10)*(3600/1000)
REKHA said:
1 decade ago
Ramesh chandran.
CLEAR explanaTION. THANKS.
CLEAR explanaTION. THANKS.
Mani said:
1 decade ago
Hi Tahira,
You just cancel 125/10 using multiples of 5.
125/10=25/2=12.5.
You just cancel 125/10 using multiples of 5.
125/10=25/2=12.5.
SHANMUGA PRIYA.TEX said:
1 decade ago
NICE EXPLANATION ABHISHEK.
Amol said:
1 decade ago
Hi Friend's
Thanks for teaching it really works dude ,
1km=1000m and 1hr =36000 then 5/18 m/sec it's simple.
Thanks for that .........!
Thanks for teaching it really works dude ,
1km=1000m and 1hr =36000 then 5/18 m/sec it's simple.
Thanks for that .........!
Amit said:
1 decade ago
Hi friend's
Hey ravi nice explanation.
Hey ravi nice explanation.
Manishkumar said:
1 decade ago
@ all apply logic don't simply go for routine
speed of man is 5km/hr and in mt/sec is 1.39.
so total distance covered by main in 10 sec is 13.9 m
so total distance covered by train in 10 sec is 125+13.9=138.9
so total distance covered by train in 1 sec is 13.89m
and if we convert this in km/hr
i.e. 13.89*3600/1000= 50km/hr
speed of man is 5km/hr and in mt/sec is 1.39.
so total distance covered by main in 10 sec is 13.9 m
so total distance covered by train in 10 sec is 125+13.9=138.9
so total distance covered by train in 1 sec is 13.89m
and if we convert this in km/hr
i.e. 13.89*3600/1000= 50km/hr
Ravi U S said:
1 decade ago
Thanks Amit
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