Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
287 comments Page 9 of 29.
Ankit said:
2 decades ago
Length of man is negligible in comparison to the train, so if cal len = 20.
Then len will calculate to the train's actual lenght.
Then len will calculate to the train's actual lenght.
Chalam said:
2 decades ago
Hi 36*54*5/18=540-> which is nothing but the total length includes train and plat form....
and 20*54*5/18=300 -> which is lenth includes train and up to man ..... and taking difference 540-300=240
and 20*54*5/18=300 -> which is lenth includes train and up to man ..... and taking difference 540-300=240
Suganthan.m said:
2 decades ago
Hi Guys
speed=15 m/s
A train passes the platform in 36 secs
15*36=540
a man standing on the platform in 20 secs
15*20=300
540-300=240
Ans:240 Am I right
speed=15 m/s
A train passes the platform in 36 secs
15*36=540
a man standing on the platform in 20 secs
15*20=300
540-300=240
Ans:240 Am I right
Nick said:
2 decades ago
Can any one explain me, if suppose
Train is takin 20s to pass the man and then 16s to pass the remaining platfom so it comes to 36s
and the speed for train is 15m/s
according to this it shoulb be 15*36= 540m
300m the point man is standing on platform and 240m for the remaining platform
Therefore 300m+240m=540m the total lenght of platform.
l-------------------m------------l
A B C
l--------20S--------l------16S---l
l---------------36s--------------l
Train is takin 20s to pass the man and then 16s to pass the remaining platfom so it comes to 36s
and the speed for train is 15m/s
according to this it shoulb be 15*36= 540m
300m the point man is standing on platform and 240m for the remaining platform
Therefore 300m+240m=540m the total lenght of platform.
Mansoorkhan said:
2 decades ago
Vetri great simple explanation keep it up thanks to all.
Raul said:
2 decades ago
Its simple and great explanation
Afroz khan said:
2 decades ago
Hello everyone.
Which is the right answer, I can understand the login given by you people, but the question raised by nick is absolutely correct. Can someone explain me in more detail so that I could clear my doubts.
Which is the right answer, I can understand the login given by you people, but the question raised by nick is absolutely correct. Can someone explain me in more detail so that I could clear my doubts.
Jagadeesh said:
2 decades ago
Hey guys u can do like this u can take the diffeerence between times i.e 36-20=16 seconds
u can change 54km/hr as meters 54*5/18=15
16*15=240meters
u can change 54km/hr as meters 54*5/18=15
16*15=240meters
Kirankumar said:
2 decades ago
Hi afkhan according to nick
The train takes to cross it self 20
The remaining 16 for platform
Refer point no 4 in formulae.
The train takes to cross it self 20
The remaining 16 for platform
Refer point no 4 in formulae.
Sid said:
2 decades ago
Satheesh your answer is simply super. Thank you.
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