Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
282 comments Page 7 of 29.
Keerthi said:
1 decade ago
If the person is standing at the starting point of the platform means the platform length is 240m otherwise its length cannot be calculated. Because if the person standing between any point of platform means it will addition of part of platform and length of train.
Shoeb said:
1 decade ago
Distance=Time*Speed.
* 54 x 5/18 = 15
* 15 x 20(given) = 300
* x+300/36=15
=240m
OR
* Distance = speed*time
* Distance = (54*5/18)*(36-20)
= 15*16
= 240
Speed , Time is given to us. We have to only apply the formula in proper way.
* 54 x 5/18 = 15
* 15 x 20(given) = 300
* x+300/36=15
=240m
OR
* Distance = speed*time
* Distance = (54*5/18)*(36-20)
= 15*16
= 240
Speed , Time is given to us. We have to only apply the formula in proper way.
Mohd Imran said:
1 decade ago
Hi friends,
length of the platform = speed*time
so,speed =54km\hr
1km=1000
1hr=60*60=3600secs
so,km/hr=1000/3600=5/18
km/hr=0.2777
so,speed =54*0.277=15
and time=36-20=16.
so length of the platform=speed*time=15*16
length of the speed =240m.
so the answer is(b)
length of the platform = speed*time
so,speed =54km\hr
1km=1000
1hr=60*60=3600secs
so,km/hr=1000/3600=5/18
km/hr=0.2777
so,speed =54*0.277=15
and time=36-20=16.
so length of the platform=speed*time=15*16
length of the speed =240m.
so the answer is(b)
Adesh Katiya said:
2 years ago
t1 =36s
t2 = 20s
s= 54km/hr
l=??
d1 = s*t
d1 = 54*(5/18) * 36
d1 = 15m/s * 36
d1 = 540m.
d2 = 15*20.
d2 = 300m.3
300m is the distance up to the man standing and the length of the total platform would be greater than this. so,
300 + x = 540m.
x = 240m.
t2 = 20s
s= 54km/hr
l=??
d1 = s*t
d1 = 54*(5/18) * 36
d1 = 15m/s * 36
d1 = 540m.
d2 = 15*20.
d2 = 300m.3
300m is the distance up to the man standing and the length of the total platform would be greater than this. so,
300 + x = 540m.
x = 240m.
(10)
Gopu said:
1 decade ago
Simple method;.
Convert train speed into m/sec=54*5/18.
=15m/s.
Subtract train time which it had taken to cross a man from the time taken by train to cross the platform i.e,
= (36-20).
=16.
Now apply formula of distance i.e. speed*time.
=15*16.
=240. ) ).
Convert train speed into m/sec=54*5/18.
=15m/s.
Subtract train time which it had taken to cross a man from the time taken by train to cross the platform i.e,
= (36-20).
=16.
Now apply formula of distance i.e. speed*time.
=15*16.
=240. ) ).
Manna said:
9 years ago
@ALL.
Logically, the length of the train should be more or less equal to the length of the platform else it will be troublesome for the passengers to cover that distance. And the solution assumes that the man is standing at the beginning of the platform.
Logically, the length of the train should be more or less equal to the length of the platform else it will be troublesome for the passengers to cover that distance. And the solution assumes that the man is standing at the beginning of the platform.
Satheesh said:
2 decades ago
Hi Guys
1 Km=1000 Meters
1 hr=3600 seconds
If the speed of the train is 54 km/hr
54*1000= 54000
54000/3600=15
A train passes a station platform in 36 seconds
15*36=540
a man standing on the platform in 20 seconds
15*20=300
540-300=240
Ans:240 Simple
1 Km=1000 Meters
1 hr=3600 seconds
If the speed of the train is 54 km/hr
54*1000= 54000
54000/3600=15
A train passes a station platform in 36 seconds
15*36=540
a man standing on the platform in 20 seconds
15*20=300
540-300=240
Ans:240 Simple
Karthik said:
2 decades ago
Shortcut:
Minus the both time of the train to cross the platform as well as man (reference point).
T = 36 sec, t = 20 sec.
T - t = 16 sec.
With the normal formula Length = Speed * Time
(i.e) 15 m/s * 16 sec = 240 metres.
Minus the both time of the train to cross the platform as well as man (reference point).
T = 36 sec, t = 20 sec.
T - t = 16 sec.
With the normal formula Length = Speed * Time
(i.e) 15 m/s * 16 sec = 240 metres.
T S SOUNDHAR said:
1 year ago
Train cross the platform is 36sec.
A man standing (passenger for boards) is = 20 sec,
Total train running time on the platform is = 36 - 20 = 16sec.
So,
54km/hr = 54000/3600 = (540/36) = 15m/s,
platform length = 16 * 15 = 240m is the answer.
A man standing (passenger for boards) is = 20 sec,
Total train running time on the platform is = 36 - 20 = 16sec.
So,
54km/hr = 54000/3600 = (540/36) = 15m/s,
platform length = 16 * 15 = 240m is the answer.
(53)
Sahil said:
2 decades ago
Distance= speed*time
300=15*20
this is length of a train only and we have to find out length of a plateform so we add length of both train and plateform becoz in case of bridge or plateform we can add both the length.
then
x+300/36=15
=240m
300=15*20
this is length of a train only and we have to find out length of a plateform so we add length of both train and plateform becoz in case of bridge or plateform we can add both the length.
then
x+300/36=15
=240m
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