Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
Speed = | ![]() |
54 x | 5 | ![]() |
18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, | x + 300 | = 15 |
36 |
x + 300 = 540
x = 240 m.
Discussion:
276 comments Page 4 of 28.
Thangapandiyan said:
1 decade ago
We have add platform lengthe(x) + tranin length(300) = total lenght (because the train enginee is pass the platform in 36 sec not tail of the train) Now we using m/s = speed formula to find unknown platform length
T navakrishna said:
1 decade ago
As man length is negligible than the train length so length of the train crossing the person is 15*20.
So time taken by the train is 20 sec and time taken by the train to cross the platform is 36 sec don't get get confused here.
So time taken by the train is 20 sec and time taken by the train to cross the platform is 36 sec don't get get confused here.
Nasir Shaikh said:
1 decade ago
Consider man is standing at the start of Platform,it takes 20 secs to cross man, but length of platorm is more than man.
Length of train = 15 * 20 = 300 m
But at 15 m/s train will last tip will take 16 more secs to cross platform i.e length of platform is 16 * 15 = 240 m
Length of train = 15 * 20 = 300 m
But at 15 m/s train will last tip will take 16 more secs to cross platform i.e length of platform is 16 * 15 = 240 m
Ankit said:
1 decade ago
Length of man is negligible in comparison to the train, so if cal len = 20.
Then len will calculate to the train's actual lenght.
Then len will calculate to the train's actual lenght.
Chalam said:
1 decade ago
Hi 36*54*5/18=540-> which is nothing but the total length includes train and plat form....
and 20*54*5/18=300 -> which is lenth includes train and up to man ..... and taking difference 540-300=240
and 20*54*5/18=300 -> which is lenth includes train and up to man ..... and taking difference 540-300=240
Suganthan.m said:
1 decade ago
Hi Guys
speed=15 m/s
A train passes the platform in 36 secs
15*36=540
a man standing on the platform in 20 secs
15*20=300
540-300=240
Ans:240 Am I right
speed=15 m/s
A train passes the platform in 36 secs
15*36=540
a man standing on the platform in 20 secs
15*20=300
540-300=240
Ans:240 Am I right
Nick said:
1 decade ago
Can any one explain me, if suppose
Train is takin 20s to pass the man and then 16s to pass the remaining platfom so it comes to 36s
and the speed for train is 15m/s
according to this it shoulb be 15*36= 540m
300m the point man is standing on platform and 240m for the remaining platform
Therefore 300m+240m=540m the total lenght of platform.
l-------------------m------------l
A B C
l--------20S--------l------16S---l
l---------------36s--------------l
Train is takin 20s to pass the man and then 16s to pass the remaining platfom so it comes to 36s
and the speed for train is 15m/s
according to this it shoulb be 15*36= 540m
300m the point man is standing on platform and 240m for the remaining platform
Therefore 300m+240m=540m the total lenght of platform.
Mansoorkhan said:
1 decade ago
Vetri great simple explanation keep it up thanks to all.
Raul said:
1 decade ago
Its simple and great explanation
Afroz khan said:
1 decade ago
Hello everyone.
Which is the right answer, I can understand the login given by you people, but the question raised by nick is absolutely correct. Can someone explain me in more detail so that I could clear my doubts.
Which is the right answer, I can understand the login given by you people, but the question raised by nick is absolutely correct. Can someone explain me in more detail so that I could clear my doubts.
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