Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
276 comments Page 3 of 28.
Lokesh said:
2 years ago
Given the speed of the train is 54 km/hr.
In 60*60second.
15m in 1 seconds.
90m in 6 seconds.
150m in 10 seconds.
240m in 16 seconds.
Because the time diff is 16 seconds Platform length.
In 60*60second.
15m in 1 seconds.
90m in 6 seconds.
150m in 10 seconds.
240m in 16 seconds.
Because the time diff is 16 seconds Platform length.
(30)
MOHAMED YAZAR S said:
2 years ago
Speed = 54km/hr
54*5/18 = 15m/s.
Time = 36-20 =16sec.
Length of the platform(D)=?
Distance = speed * time.
Distance = 15 * 16.
Distance = 240 m.
54*5/18 = 15m/s.
Time = 36-20 =16sec.
Length of the platform(D)=?
Distance = speed * time.
Distance = 15 * 16.
Distance = 240 m.
(222)
Lithesh kumar said:
2 years ago
Speed=54*5/18=15m/s.
Distance = 36 - 20s = 16,
=>15*16=240m.
Distance = 36 - 20s = 16,
=>15*16=240m.
(25)
Justin Gj said:
2 years ago
Since the options given are in meters, we must first convert given into m/s.
Speed of train =54km/hr = 54*5/18 = 15m/s.
Then find the length of the train using D = S * T eqn in the case of a man
Length of train =15 m/s *20 secs =300m.
Then while passing the platform, Total length =(train length +platform length) = 15m/s * 36 secs =540m.
Therefore platform length = 540m - 300m = 240m.
Speed of train =54km/hr = 54*5/18 = 15m/s.
Then find the length of the train using D = S * T eqn in the case of a man
Length of train =15 m/s *20 secs =300m.
Then while passing the platform, Total length =(train length +platform length) = 15m/s * 36 secs =540m.
Therefore platform length = 540m - 300m = 240m.
(41)
Priyanka said:
2 years ago
D = S x T.
D = (54x 5*18) x (36-20).
D = 15 x 16.
D = 240m/s.
D = (54x 5*18) x (36-20).
D = 15 x 16.
D = 240m/s.
(157)
Rejwan Hossain said:
3 years ago
The length of the platform = (speed of train * time taken to pass the platform)/(1 - (time taken to pass the man/time taken to pass the platform))
In this case:
The length of platform = (54 * 36)/(1 - (20 / 36))
= (54*36)/(1-(20/36))
= (1944)/(1-(5/9))
= 1944/(4/9)
= 1944 * (9/4) = 240 meters.
In this case:
The length of platform = (54 * 36)/(1 - (20 / 36))
= (54*36)/(1-(20/36))
= (1944)/(1-(5/9))
= 1944/(4/9)
= 1944 * (9/4) = 240 meters.
(11)
Dipesh said:
3 years ago
54 * 5/18 = 15m/sec.
20 + 36sec = 56sec,
15 * 56 = 240m.
20 + 36sec = 56sec,
15 * 56 = 240m.
(61)
Ravi Kumar said:
3 years ago
The length of platform = x + 300/36 = 15 m/s.
Can someone explain why we write the 15 m/s on R.H.S of the equation?
I really could not understand. If someone knows then please help me.
Can someone explain why we write the 15 m/s on R.H.S of the equation?
I really could not understand. If someone knows then please help me.
(5)
Anusha said:
3 years ago
Speed = l + b (length of train +platforn).
Speed of train = 54*5/18 = 15.
speed = d/t -----> d = s*t.
d = 15*36-20 (time of train - time of man).
d = 240m.
Speed of train = 54*5/18 = 15.
speed = d/t -----> d = s*t.
d = 15*36-20 (time of train - time of man).
d = 240m.
(18)
Noradavis said:
3 years ago
@All.
Since the train is moving toward the man you can do 36-20 seconds = 16 seconds.
Since the train is moving toward the man you can do 36-20 seconds = 16 seconds.
(8)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers