Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
276 comments Page 24 of 28.
Sachin kamble said:
1 decade ago
Train passes the plat form in 36 sec and man standing on platform i.e 20 sec so the time 16 sec by 36-20=16 then apply speed=distance/time we have speed 54km/hr that to be converted in to m/sec because we need length in meter. So 54*[5/18] = 15 m/sec.
Then distance = 16*15 = 240.
Then distance = 16*15 = 240.
Suresh said:
1 decade ago
Satheesh your answer is very easy and simple way of maintain the problem solution. Thank you.
Sabarish said:
1 decade ago
@saikiran
here speed of the train given as in km/hr . so first we convert it into m/sec [i.e 54km/hr*(5/18)=15m/sec]. 5/18 is used to convert train speed into m/sec.
Then if you want length of the train means,you;ll use below formula:
Length of the Train=Speed*time
It is general formula in train based questions..
Have a nice day for you..
here speed of the train given as in km/hr . so first we convert it into m/sec [i.e 54km/hr*(5/18)=15m/sec]. 5/18 is used to convert train speed into m/sec.
Then if you want length of the train means,you;ll use below formula:
Length of the Train=Speed*time
It is general formula in train based questions..
Have a nice day for you..
Sid said:
1 decade ago
Satheesh your answer is simply super. Thank you.
Kirankumar said:
1 decade ago
Hi afkhan according to nick
The train takes to cross it self 20
The remaining 16 for platform
Refer point no 4 in formulae.
The train takes to cross it self 20
The remaining 16 for platform
Refer point no 4 in formulae.
Jagadeesh said:
1 decade ago
Hey guys u can do like this u can take the diffeerence between times i.e 36-20=16 seconds
u can change 54km/hr as meters 54*5/18=15
16*15=240meters
u can change 54km/hr as meters 54*5/18=15
16*15=240meters
Afroz khan said:
1 decade ago
Hello everyone.
Which is the right answer, I can understand the login given by you people, but the question raised by nick is absolutely correct. Can someone explain me in more detail so that I could clear my doubts.
Which is the right answer, I can understand the login given by you people, but the question raised by nick is absolutely correct. Can someone explain me in more detail so that I could clear my doubts.
Raul said:
1 decade ago
Its simple and great explanation
Mansoorkhan said:
1 decade ago
Vetri great simple explanation keep it up thanks to all.
Nick said:
1 decade ago
Can any one explain me, if suppose
Train is takin 20s to pass the man and then 16s to pass the remaining platfom so it comes to 36s
and the speed for train is 15m/s
according to this it shoulb be 15*36= 540m
300m the point man is standing on platform and 240m for the remaining platform
Therefore 300m+240m=540m the total lenght of platform.
l-------------------m------------l
A B C
l--------20S--------l------16S---l
l---------------36s--------------l
Train is takin 20s to pass the man and then 16s to pass the remaining platfom so it comes to 36s
and the speed for train is 15m/s
according to this it shoulb be 15*36= 540m
300m the point man is standing on platform and 240m for the remaining platform
Therefore 300m+240m=540m the total lenght of platform.
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